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definition of a midpoint definition of an angle bisector

meryl avatar
meryl
29 diapositives · 536 Views · Sep 03, 2014

definition of a midpoint definition of an angle bisector. A. B. C. Given: B is midpoint of AC Prove: AB = BC. Statement Reason B is midpoint of AC given. A. B. C. Given: B is midpoint of AC Prove: AB = BC. Statement Reason B is midpoint of AC given

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  1. definition of a midpoint definition of an angle bisector

  2. A B C Given: B is midpoint of AC Prove: AB = BC StatementReason B is midpoint of AC given

  3. A B C Given: B is midpoint of AC Prove: AB = BC StatementReason B is midpoint of AC given AB = BC definition of midpoint

  4. A B C Given: B is midpoint of AC Prove: AC = 2(BC) StatementReason B is midpoint of AC given

  5. A B C Given: B is midpoint of AC Prove: AC = 2(BC) StatementReason B is midpoint of AC given AB = BC definition of midpoint

  6. A B C Given: B is midpoint of AC Prove: AC = 2(BC) StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate

  7. A B C Given: B is midpoint of AC Prove: AC = 2(BC) StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate AC = BC + BC substitution

  8. A B C Given: B is midpoint of AC Prove: AC = 2(BC) StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate AC = BC + BC substitution AC = 2(BC) combine like terms

  9. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given

  10. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given AB = BC definition of midpoint

  11. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate

  12. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate AC = BC + BC substitution

  13. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate AC = BC + BC substitution AC = 2(BC) combine like terms

  14. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate AC = BC + BC substitution AC = 2(BC) combine like terms (1/2)AC = BC division property

  15. A B C Given: B is midpoint of AC Prove: BC = (1/2)AC StatementReason B is midpoint of AC given AB = BC definition of midpoint AC = AB + BC segment addition postulate AC = BC + BC substitution AC = 2(BC) combine like terms (1/2)AC = BC division property BC = (1/2)AC symmetric property

  16. A B Given: BD bisects <ABC Prove: <1 = <2 <1 <2 D C StatementReason BD bisects <ABC given

  17. A B Given: BD bisects <ABC Prove: <1 = <2 <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector

  18. A B Given: BD bisects <ABC Prove: <ABC = 2(<1) <1 <2 D C StatementReason BD bisects <ABC given

  19. A B Given: BD bisects <ABC Prove: <ABC = 2(<1) <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector

  20. A B Given: BD bisects <ABC Prove: <ABC = 2(<1) <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate

  21. A B Given: BD bisects <ABC Prove: <ABC = 2(<1) <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate <ABC = <1 + <1 substitution

  22. A B Given: BD bisects <ABC Prove: <ABC = 2(<1) <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate <ABC = <1 + <1 substitution <ABC = 2(<1) combine like terms

  23. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given

  24. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector

  25. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate

  26. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate <ABC = <1 + <1 substitution

  27. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate <ABC = <1 + <1 substitution <ABC = 2(<1) combine like terms

  28. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate <ABC = <1 + <1 substitution <ABC = 2(<1) combine like terms (1/2)<ABC = <1 division property

  29. A B Given: BD bisects <ABC Prove: <1 = (1/2)<ABC <1 <2 D C StatementReason BD bisects <ABC given <1 = <2 definition of angle bisector <ABC = <1 + <2 angle addition postulate <ABC = <1 + <1 substitution <ABC = 2(<1) combine like terms (1/2)<ABC = <1 division property <1 = (1/2)<ABC symmetric property