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Solutions

Solutions. A solution is a homogenous mixture whose component substances cannot be distinguished. Eg: Salt water, Gatorade, tap water, vodka, Kool-Aid. SOLUTION. Made up of. SOLUTE. SOLVENT. The substance dissolved, usually a solid. The liquid the solute is dissolved in (Ex. water).

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Solutions

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  1. Solutions • A solution is a homogenous mixture whose component substances cannot be distinguished. • Eg: Salt water, Gatorade, tap water, vodka, Kool-Aid.

  2. SOLUTION Made up of SOLUTE SOLVENT The substance dissolved, usually a solid The liquid the solute is dissolved in (Ex. water)

  3. Common Solutions in the world….. Orange Juice Solute: orange concentrate Solvent: water sdfsdf Salt Water Solute: salt Solvent: water Chocolate Milk Solute: chocolate powder Solvent: milk http://www.nrprcd.org/photo_gallery/rcd_03/coordinator_breakfast/images/orange_juice.jpg http://www.seedownunder.com.au/destination/queensland/noosa/noosa-accommodation/noosa-heads/ocean_breeze/images/OCEAN_BREEZE_BEACH.JPG

  4. Aqueous Solution • An aqueous solution is one in which the solvent is water

  5. CONCENTRATION (C) C = Measurement of the amount of solute that is dissolved in a given amount of solution Mass of solute (g) __________ Volume of solution (L) C = M V g/L

  6. Example: • A solution with concentration of 10 g/L will have 10 grams of solute for every 1 L (1000ml) of solution • When comparing solutions be sure to have the same unit of measurement (grams/litre) • NOTE: To ensure you always have the correct units for concentration (grams/litre) we will the change the formula slightly: IMPORTANT 1 L = 1000ml C = g L C = M V

  7. Concentration 2 scoops 1 scoop 1 litre of solvent 1 litre of solvent

  8. EXAMPLE #1 What is the concentration of a solution that has volume of 500ml and contains 40 g of solute? C = M V C = g 1 L or C = ? G = 40 g L = 0.5 L C = 40 g C = 80g/L 0.5 L

  9. Example # 2 You have a 5 g/L of a salt solution with a volume of 50 ml. What is the amount of solute (salt) in this solution? C=M V C=g L GIVEN INFORMATION C = 5 g/L G = ? L = 0.05 L Cross multiply 50 ml = 0.05 L

  10. Each can contains sugar ( ) and water. Which can has the strongest concentration? Remember…Keep the units the same!! = 1 particle (1g) Water (50ml) Water (25 ml) Water (0.25 L) Water (125ml) A B C D C = 100 g/L C = 80 g/L C = 28 g/L C = 32 g/L

  11. EXAMPLE #3: How much solute is there in a 50g/L solution if it has a volume of 250ml? C = g L C = 50 g/L G = ? L = 250ml .25L 50 = ? G = 12.5 g 0.25 L

  12. Example # 4 You have a solution that has a concentration of 22 g/L. There is 30 grams of solute in this solution. What is the volume in milliliters of the solution? C=M V GIVEN INFORMATION C = 22 g/L G = 30 L = ? Cross multiply The volume of the solution is 1360 ml.

  13. PREPARING A SOLUTION • Place about half the amount of solvent (liquid) into container • Add the solute • Dissolve by shaking or swirling • Add the rest of the solvent (liquid) to reach the desired volume DO NOT put all of the solvent and solute together at once…inaccurate results!

  14. Example # 6 Describe the procedure that would be used to prepare 250 ml of a sugar solution that has a concentration of 13 g/L. BE SPECIFIC…… Find out you how much grams you need. C=g L Step #1 Step #2 Write out procedure using a step by step method! 1. Pour half of the required volume (125 ml) into a beaker 2. Add the solute (3.25 grams) to the beaker 3. Mix them together 4. Add the solvent (liquid) until you reach the desired amount (250 ml)

  15. KEY POINTS • Concentration Formula C =M/V (C=g/L) • To Prepare a Solution You…. -pour half of required amount of solvent in beaker -Add desired amount of solute -Mix -Add solvent (liquid) till your beaker reaches the required amount

  16. PRACTICE PROBLEMS • Study guide, Module 3, page 14 • Text book page 351 # 5, 6, 7 • Worksheet # 4

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