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Entry Task: March 4 th Monday

Pick up papers in Lab area. Entry Task: March 4 th Monday. Sign off and Discuss. Agenda:. Discuss Stoichiometry 2 ws Walk through Label reasoning Label Reasoning ws 2. 1. Balance the Rxn : Potassium bromide reacts with magnesium metal creates potassium metal + magnesium bromide . 2.

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Entry Task: March 4 th Monday

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  1. Pick up papers in Lab area Entry Task: March 4thMonday Sign off and Discuss

  2. Agenda: • Discuss Stoichiometry 2 ws • Walk through Label reasoning • Label Reasoning ws 2

  3. 1. Balance the Rxn: Potassium bromide reacts with magnesium metal creates potassium metal + magnesium bromide 2 _____KBr+ _____Mg _____MgBr2 + _____ K 2 a. How many moles of magnesium were used to create 0.365 moles of magnesium bromide? Units match 1 molMg 0.365 moles of MgBr2 0.365 = moles Mg 1 molMgBr2

  4. 2 _____KBr+ _____Mg _____MgBr2 + _____ K 2 b. How many moles of potassium bromide are needed to react with 3.47 moles of magnesium? Units match 2 molKBr 3.47 moles of Mg = moles KBr 6.94 1 mol Mg

  5. 2 _____KBr+ _____Mg _____MgBr2 + _____ K 2 c. How many moles of magnesium bromide were produced if 20.0g of magnesium were used? Units match 20.0 g Mg 1 molMg 1 molMgBr2 = moles MgBr2 0.823 24.305 g Mg 1 molMg 20.0 X 1 = 20.0 24.305 X 1 = 24.305

  6. 2 _____KBr+ _____Mg _____MgBr2 + _____ K 2 d. How many moles of potassium bromide were used if 316g of magnesium bromide were produced? Units match 316 g MgBr2 1 molMgBr2 2 molKBr = moles KBr 3.43 184.10 g MgBr2 1 molMgBr2 316 X 2 = 632 184.10 X 1 = 184.10

  7. 2. Tin IV oxide reacts with hydrogen monofluoride to create Tin IV fluoride and water 4 2 _____SnO2 + _____HF  _____SnF4 + _____H2O a. How many moles of Tin IV oxide were used to create 5.26 moles of water? Units match 1 mol SnO2 5.26 moles of H2O 2.63 = moles SnO2 2 mol H2O

  8. 4 2 _____SnO2 + _____HF  _____SnF4 + _____H2O b. How many moles of hydrogen monofluoride were used to create 0.895 moles of Tin IV fluoride? Units match 4 mol HF 0.895 moles of SnF4 3.58 = moles HF 1 mol SnF4

  9. 4 2 _____SnO2 + _____HF  _____SnF4 + _____H2O c. How many moles of Tin IV fluoride were produced if 326 g of hydrogen monofluoride were used? Units match 326 g HF 1 mol HF 1 mol SnF4 = moles SnF4 4.08 20.00 g HF 4 mol HF 326 X 1 = 326 20.00 X 4 = 80

  10. 4 2 _____SnO2 + _____HF  _____SnF4 + _____H2O d. How many moles of Tin IV oxide were used if 1.25 g of Tin IV fluoride were produced? Units match 1.25g SnF4 1 mol SnF4 1 mol SnO2 = moles SnO2 0.00642 194.7 g SnF4 1 mol SnF4 1.25 X 1 = 1.25 194.7 X 1 = 194.7

  11. Cobalt metal reacts with lead II phosphate to create lead metal to cobalt II phosphate 3 3 _____Co + _____Pb3(PO4)2 _____Pb + _____Co3(PO4)2 a. How many moles of Lead II phosphate were used to create 0.812 moles of lead metal? Units match 1 mol Pb3(PO4)2 0.812moles of Pb 0.271 = moles Pb3(PO4)2 3 mol Pb

  12. Cobalt metal reacts with lead II phosphate to create lead metal to cobalt II phosphate 3 3 _____Co + _____Pb3(PO4)2 _____Pb + _____Co3(PO4)2 b. How many moles of Cobalt metal were used to create 26.7 moles of Cobalt II phosphate? Units match 3 mol Co 26.7moles of Co3(PO4)2 80.1 = moles Co 1 mol Co3(PO4)2

  13. Cobalt metal reacts with lead II phosphate to create lead metal to cobalt II phosphate 3 3 _____Co + _____Pb3(PO4)2 _____Pb + _____Co3(PO4)2 c. How many moles of Lead were produced if 23.8 g of Cobalt were used? Units match 23.8 g Co 1 mol Co 3 mol Pb = moles Pb 0.404 58.933 g Co 3 mol Co 23.8 X 3 = 71.4 58.933 X 3 = 176.799

  14. Cobalt metal reacts with lead II phosphate to create lead metal to cobalt II phosphate 3 3 _____Co + _____Pb3(PO4)2 _____Pb + _____Co3(PO4)2 d. How many moles of Lead II phosphate were used if 0.65 g of Cobalt II phosphate were produced? Units match 0.65 g Co3(PO4)2 1 mole Co3(PO4)2 1 mol Pb3(PO4)2 = moles Pb3(PO4)2 0.0018 366.92g Co3(PO4)2 1 mol Co3(PO4)2 0.65 X 1 = 0.65 366.92 X 1 = 366.92

  15. Nickel metal reacts with aluminum sulfate creates aluminum metal and nickel IV sulfate 3 2 4 3 _____Ni + _____Al2(SO4)3  _____ Al + _____ Ni(SO4)2 a. How many moles of nickel were used to create 0.650 moles of nickel IV sulfate? Units match 3 mol Ni 0.650 moles of Ni(SO4)2 = moles Ni 0.650 3 mol Ni(SO4)2

  16. Nickel metal reacts with aluminum sulfate creates aluminum metal and nickel IV sulfate 3 2 4 3 _____Ni + _____Al2(SO4)3  _____ Al + _____ Ni(SO4)2 b. How many moles of Aluminum sulfate were used to create 7.25 moles of aluminum metal? Units match 2 mol Al2(SO4)3 7.25moles of Al = moles Al2(SO4)3 3.63 4 mol Al

  17. Nickel metal reacts with aluminum sulfate creates aluminum metal and nickel IV sulfate 3 2 4 3 _____Ni + _____Al2(SO4)3  _____ Al + _____ Ni(SO4)2 c. How many moles of Nickel IV sulfate were produced if 85.0 g of Aluminum sulfate were used? Units match 85.0 g Al2(SO4)3 1 mole Al2(SO4)3 3 mol Ni(SO4)2 = moles Ni(SO4)2 0.373 342.147 g Al2(SO4)3 2 mol Al2(SO4)3 85.0 X 3 = 255 342.147 X 2 = 684.294

  18. Nickel metal reacts with aluminum sulfate creates aluminum metal and nickel IV sulfate 3 2 4 3 _____Ni + _____Al2(SO4)3  _____ Al + _____ Ni(SO4)2 d. How many moles of nickel were used if 3.54 g of Aluminum were produced? Units match 3.54 g Al 1 mole Al 3 mol Ni = moles Ni 0.0984 26.982 g Al 4 mol Al 3.54 X 3 = 10.62 26.987 X 4 = 107.95

  19. I can… • Use the sequence of steps used in solving stoichiometric problems

  20. Label Reasoning

  21. Calcium metal reacts with aluminum bromide to create calcium bromide and aluminum metal 2 3 2 3 ___Ca + ___AlBr3 ___CaBr2 + ___Al

  22. How many moles of aluminum bromide are needed to produce 0.75 moles of calcium bromide? moles of AlBr3, 0.75 moles of CaBr2, 2 moles of AlBr3, 3 moles of CaBr2, moles of CaBr2, its our starting amount moles of AlBr3, its what we are asking for moles of CaBr2, because its diagonal from starting (mole ratio) moles of AlBr3, needs to be on top to match our end label (mole ratio) 0.50 moles of AlBr3, Plug in and provide answer to B= ________________________

  23. How many moles of calcium are needed if 45.0 grams of calcium bromide are produced? 45.0 grams of CaBr2, moles of Ca g of CaBr2 grams of CaBr2, its our starting amount moles of Ca, its what we are asking for grams of CaBr2, because its diagonal from starting information

  24. How many moles of calcium are needed if 45.0 grams of calcium bromide are produced? 45.0 grams of CaBr2, moles of Ca moles of CaBr2 moles of Ca g of CaBr2 moles of CaBr2 moles of Ca, needs to be on top to match our end label moles of CaBr2, needs to be on bottom for the correct mole ratio moles of CaBr2, needs to be on top for the correct mole to gram conversion

  25. How many moles of calcium are needed if 45.0 grams of calcium bromide are produced? 3 moles of Ca 1 moles of CaBr2 45.0 grams of CaBr2, moles of Ca 199.89 g of CaBr2 3 moles of CaBr2 0.225 moles of Ca, Plug in and provide answer to B= ________________________

  26. How many grams of aluminum are produced if 10.0 moles of calcium are used? 10.0 moles of Ca, grams of Al moles of Ca moles of Ca, its our starting amount grams of Al, its what we are asking for moles of Ca, because its diagonal from starting information

  27. How many grams of aluminum are produced if 10.0 moles of calcium are used? grams of Al 10.0 moles Ca, moles of Al grams of Al moles of Al moles of Ca grams of Al, needs to be on top to match our end label moles of Al, needs to be on bottom for the correct mole to gram ratio moles of Al, needs to be on top for the correct mole ratio and diagonal from moles of Al

  28. How many grams of aluminum are produced if 10.0 moles of calcium are used? 26.982 grams of Al 10.0 moles Ca, 2 moles of Al grams of Al 1 moles of Al 3 moles of Ca 1.80 x102grams of Al Plug in and provide answer to B= ________________________ 180 grams of Al

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