1 / 29

Number systems

Number systems. Converting numbers between binary, octal, decimal, hexadecimal (the easy way). Small numbers are easy to convert. But it helps to have a system for converting larger numbers to avoid errors. 12 10 = C 16. 5 10 -> 101 2. 1100 2 = 12 10. DEMONSTRATE.

nia
Télécharger la présentation

Number systems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Number systems Converting numbers between binary, octal, decimal, hexadecimal (the easy way)

  2. Small numbers are easy to convert • But it helps to have a system for converting larger numbers to avoid errors. 1210 = C16 510 -> 1012 11002 = 1210

  3. DEMONSTRATE Converting from base 10 (decimal)to base 2 (binary) example number = 42 • Write the powers of 2 in a row starting on the RIGHT side with a 1 • Keep doubling (*2) until you get to something greater than your number (42) 64 32 16 8 4 2 1 This is too big 1 0 1 1 3. Write a 1 underneath if that place value is used, 0 if not. subtract to find out what is left. 0 0 42 -32 ---- 10 10 - 8 ---- 2 2 -2 ---- 0 Watch Read your answer from left to right The number in binary is 101010

  4. DO TOGETHER Converting from base 10 (decimal)to base 2 (binary) example number = 7053 • write the powers of 2 in a row until you get to something > the number 8192 4096 2048 1024 512 256 128 64 32 16 8 4 2 1 Too big 0 1 1 0 1 1 1 0 0 0 1 1 1 7053 -4096 ------- 2957 2957 -2048 ------- 909 909 - 512 ------- 397 397 -256 ------ 141 141 -128 ------- 13 13 - 8 ----- 5 5 -4 --- 1 1 -1 --- 0 Do this together the number in binary is 1101110001101

  5. STUDENT’S TURN Do this one 15010 binary • 1 • 2 • 4 • 8 • 16 • 32 • 64 • 128 • 256 1 0 Too big 1 0 0 1 0 1 Click to see each digit that is needed. The answer is: 10010110

  6. To convert binary to decimal the number in binary is 10111001101 • Write the powers of 2 below each digit and only add the values with a 1 above them. • 0 1 1 1 0 0 1 1 0 1 • 1024 512 256 128 64 32 16 8 4 2 1 Start at the right and double each number 1024 + 256+128+64 + 8 + 4 + 1 = 1,485 Watch

  7. Your turn. Convert 1000100112 to decimal • 1 0 0 0 1 0 0 1 1 • 256 128 64 32 16 8 4 2 1 • 256 + 16 + 2+1 = • 275 • …. And now, for more about number systems.

  8. Part 2 • Number Systems

  9. Quick review • What’s 41 in binary? • 32 16 8 4 2 1 • 1 0 1 0 0 1 The answer is: 101001

  10. Quick Review: binary to decimal • 10011012 decimal • 64 + 8 + 4 + 1 • =77

  11. An Introduction toHexadecimal • 16 digits • Use letters when you run out of single digits • 0 1 2 3 4 5 6 7 8 9 A B C D E F • SO… 1110 = ?16 • B16 • 1510 = ? • F16 • 1610 = ? • 1016

  12. from base 10 to base 16 (decimal tohexadecimal) example number = 7053 • write the powers of 16 in a row until you get to one > the number • divide the number by each power of 16 and write the answer and save the remainder 65,536 4,096 256 16 1 • Too high • 7053/4096 = 1 R 2957 • 2957/256 = 11 R 141 • 141/16 = 8 R 13 • 13 ones • the numbers in hex are: • 1 2 3 4 5 6 7 8 9 A B C D E F (A=10…. F=15) • So your number is 1 11 8 13 = 1B8D16 Watch

  13. Do this one • 96210 hexadecimal • 3C216 • This is 3*256 + C(10)*16 + 2

  14. from hexadecimal (base 16) back to decimal Watch 1B8D16 • Write the number across a row. Write the powers of 16 below it. Multiply. Then add the products. • 1 B 8 D • =(1X4096)+ • (11*256)+ • (8*16)+(13*1) = • 4096 + 2816 + 128 + 13 = 7053 4096 256 16 1

  15. Do this one • A10E16 decimal • 41230

  16. Octal • Base 8 • Uses 8 different digits • 0 1 2 3 4 5 6 7

  17. from base 10 to base 8(decimal tooctal) example number = 7053 • write the powers of 8 in a row until you get to one > the number • divide the number by each power of 8 • write the answer and save the remainder • 32768 4096 512 64 8 1 • too high • 7053/4096 = 1 R 2957 • 2957/512 = 5 R 397 • 397/64 = 6 R 13 • 13/8 = 1 R 5 • = 5 ones • so your number in octal is 156158 Watch

  18. Do this one: • 94610 octal • 16628

  19. from octal (base 8) back to decimal 156158 • write the number • write the powers of 8 below it and multiply. then add the products. • 1 5 6 1 5 • 4096 512 64 8 1 • 1 *4096 = 4096 • 5 * 512 = 2560 • 6 * 64 = 384 • 1* 8 = 8 • 5 * 1 = 5 • added together = 7053 Watch

  20. Do this one • 20458 • 106110

  21. 0 1 10 11 100 101 110 111 1000 1001 1010 1011 1100 1101 1110 1111 Binary  hex  octal • If you can count from 1 to 15 in binary you have it made

  22. Binary to hexadecimal and hex to binary Watch • 4 binary digits correspond to 1 hexadecimal digit • Start grouping digits on the RIGHT side • 0000 0 • 0001 1 • 0010 2 • 0011 3 • 0100 4 • 0101 5 • 0110 6 • 0111 7 • 1000 8 • 1001 9 • 1010 A • 1011 B • 1100 C • 1101 D • 1110 E • 1111 F To convert binary 1101011110 to hex Binary  Hexadecimal 11 0101 1110 3 5 E 35E16 Write this down the side of your paper. Hex  Binary 28D1 10 1000110100012

  23. Practice Hex  Binary  Hex • Convert E5816 to Binary • 111001011000 • Convert 110010110 to Hexadecimal • 196

  24. binary to octal and octal to binary • 3 binary digits correspond to 1 octal digit • 000 0 • 001 1 • 010 2 • 011 3 • 100 4 • 101 5 • 110 6 • 111 7 Binary to octal 10110011 10 110 011 263 • Octal to binary • 451 • 100 101 001 • 101001 Watch

  25. Practice Octal  Binary  Octal • Convert 3078 to Binary • 11000111 • Convert 110010110 to Octal • 646

  26. octal to hex and hex to octal. • Convert to binary, regroup and convert to other base. Octal to binary to hex 4518 100 101 001 100101001 1 0010 1001 12916 Watch

  27. Practice Octal  Hex • Convert 3078 to Hex • 11 000 111 first in binary • 11000111 • 1100 0111 divide into groups of 4 • 12 7 • C716

  28. Practice Hex  Octal • Convert 2B1D16 to Octal • 10 1011 0001 1101 first in binary • 10101100011101 • 10 101 100 011 101 divide into groups of 3 • 2 5 4 3 5 • 254358

  29. The End

More Related