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Section 15.8.

FREE EXTREMUM VERSUS CONSTRAINED EXTREMUM PROBLEMS. To find the minimum value off (x, y, z) = x2 2y2 z4 4is a free extremum problem. To find the minimum off (x, y, z) = x2 2y2 z4 4subject to the condition that x 3y - z = 7 is a constrained extremum problem. . AN EXAMPLE. Maximize t

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Section 15.8.

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Presentation Transcript

    1. Section 15.8. Lagrange Multipliers

    2. FREE EXTREMUM VERSUS CONSTRAINED EXTREMUM PROBLEMS

    3. AN EXAMPLE

    4. NOTES ON THE EXAMPLE

    5. THE EXAMPLE REPHRASED

    6. METHOD OF LAGRANGE MULTIPLIERS

    7. THE METHOD OF LAGRANGE MULTIPLIERS WITH PARTIAL DERIVATIVES

    8. EXAMPLES

    9. THE METHOD OF LAGRANGE MULTIPLIERS WITH TWO CONSTRAINTS

    10. THE PARTIAL DERIVATIVE FORM FOR TWO CONSTRAINTS

    11. EXAMPLE

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