1 / 42

Chapter 10 Comparisons Involving Means

Chapter 10 Comparisons Involving Means. Inferences About the Difference Between Two Population Means: when s 1 and s 2 Known. Inferences About the Difference Between Two Population Means: when s 1 and s 2 Unknown. Inferences About the Difference Between

olesia
Télécharger la présentation

Chapter 10 Comparisons Involving Means

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 10 Comparisons Involving Means • Inferences About the Difference Between Two Population Means: when s1 and s2 Known • Inferences About the Difference Between Two Population Means: when s1 and s2 Unknown • Inferences About the Difference Between Two Population Means: Matched Samples • Introduction to Analysis of Variance (Inference about the difference between more than two population means

  2. Inferences About the Difference BetweenTwo Population Means: s 1 and s 2 Known • Interval Estimation of m1 – m2 • Hypothesis Tests About m1 – m2

  3. Let equal the mean of sample 1 and equal the mean of sample 2. • The point estimator of the difference between the • means of the populations 1 and 2 is . Estimating the Difference BetweenTwo Population Means • Let 1 equal the mean of population 1 and 2 equal the mean of population 2. • The difference between the two population means is 1 - 2. • To estimate 1 - 2, we will select a simple random sample of size n1 from population 1 and a simple random sample of size n2 from population 2.

  4. Sampling Distribution of • Expected Value • Standard Deviation (Standard Error) where: 1 = standard deviation of population 1 2 = standard deviation of population 2 n1 = sample size from population 1 n2 = sample size from population 2

  5. Interval Estimation of 1 - 2:s 1 and s 2 Known • Interval Estimate where: 1 -  is the confidence coefficient

  6. Interval Estimation of 1 - 2:s 1 and s 2 Known • Example: Par, Inc. is a manufacturer of golf equipment and has developed a new golf ball that has been designed to provide “extra distance.” In a test of driving distance using a mechanical driving device, a sample of Par golf balls was compared with a sample of golf balls made by Rap, Ltd., a competitor. The sample statistics appear on the next slide.

  7. Interval Estimation of 1 - 2:s 1 and s 2 Known Sample #1 Par, Inc. Sample #2 Rap, Ltd. Sample Size 120 balls 80 balls Sample Mean 275 yards 258 yards Based on data from previous driving distance tests, the two population standard deviations are known with s 1 = 15 yards and s 2 = 20 yards.

  8. Interval Estimation of 1 - 2:s 1 and s 2 Known Develop a 95% confidence interval estimate of the difference between the mean driving distances of the two brands of golf ball.

  9. Population 1 Par, Inc. Golf Balls m1 = mean driving distance of Par golf balls Population 2 Rap, Ltd. Golf Balls m2 = mean driving distance of Rap golf balls Simple random sample of n1 Par golf balls x1 = sample mean distance for the Par golf balls Simple random sample of n2 Rap golf balls x2 = sample mean distance for the Rap golf balls x1 - x2 = Point Estimate of m1 –m2 Estimating the Difference BetweenTwo Population Means m1 –m2= difference between the mean distances

  10. Point Estimate of 1 - 2 Point estimate of 1-2 = = 275 - 258 = 17 yards where: 1 = mean distance for the population of Par, Inc. golf balls 2 = mean distance for the population of Rap, Ltd. golf balls

  11. Interval Estimation of 1 - 2:1 and 2 Known 17 + 5.14 or 11.86 yards to 22.14 yards We are 95% confident that the difference between the mean driving distances of Par, Inc. balls and Rap, Ltd. balls is 11.86 to 22.14 yards.

  12. Hypothesis Tests About m 1-m 2:s 1 and s 2 Known • Hypothesis Testing Left-tailed Right-tailed Two-tailed • Test Statistic

  13. Hypothesis Tests About m 1-m 2:s 1 and s 2 Known Can we conclude, using a = .01, that the mean driving distance of Par, Inc. golf balls is greater than the mean driving distance of Rap, Ltd. golf balls?

  14. Hypothesis Tests About m 1-m 2:s 1 and s 2 Known H0: 1 - 2< 0 Ha: 1 - 2 > 0 1. Develop the hypotheses. where: 1 = mean distance for the population of Par, Inc. golf balls 2 = mean distance for the population of Rap, Ltd. golf balls 2. Specify the level of significance. a = .01

  15. Hypothesis Tests About m 1-m 2:s 1 and s 2 Known 3. Compute the value of the test statistic.

  16. Hypothesis Tests About m 1-m 2:s 1 and s 2 Known • Using the Critical Value Approach 4. Determine the critical value and rejection rule. For a = .01, z.01 = 2.33 5. Compare the Test Statistic with the Critical Value. Because z = 6.49 > 2.33, we reject H0. The sample evidence indicates the mean driving distance of Par, Inc. golf balls is greater than the mean driving distance of Rap, Ltd. golf balls.

  17. Hypothesis Tests About m 1-m 2:s 1 and s 2 Known • Using the p –Value Approach 4. Compute the p–value. For z = 6.49, the p –value < .0001. 5. Determine whether to reject H0. Because p–value <a = .01, we reject H0. At the .01 level of significance, the sample evidence indicates the mean driving distance of Par, Inc. golf balls is greater than the mean driving distance of Rap, Ltd. golf balls.

  18. Inferences About the Difference BetweenTwo Population Means: s 1 and s 2 Unknown • Interval Estimation of m1 – m2 • Hypothesis Tests About m1 – m2

  19. Interval Estimation of 1 - 2:s 1 and s 2 Unknown When s 1 and s 2 are unknown, we will: • we use the sample standard deviations s1 and s2 • as estimates of s 1 and s 2 , and • replace za/2 with ta/2.

  20. Interval Estimation of 1 - 2:s 1 and s 2 Unknown • Interval Estimate Where the degrees of freedom for ta/2 are:

  21. Difference Between Two Population Means: s 1 and s 2 Unknown • Example Specific Motors of Detroit has developed a new automobile known as the M car. 24 M cars and 28 J cars (from Japan) were road tested to compare miles-per-gallon (mpg) performance. The sample statistics are shown on the next slide.

  22. Difference Between Two Population Means: s 1 and s 2 Unknown Sample #2 J Cars Sample #1 M Cars 24 cars 28 cars Sample Size 29.8 mpg 27.3 mpg Sample Mean 2.56 mpg 1.81 mpg Sample Std. Dev.

  23. Difference Between Two Population Means: s 1 and s 2 Unknown Develop a 90% confidence interval estimate of the difference between the mpg performances of the two models of automobile.

  24. Point Estimate of m 1-m 2 Point estimate of 1-2 = = 29.8 - 27.3 = 2.5 mpg where: 1 = mean miles-per-gallon for the population of M cars 2 = mean miles-per-gallon for the population of J cars

  25. Interval Estimation of m 1-m 2:s 1 and s 2 Unknown The degrees of freedom for ta/2 are: With a/2 = .05 and df = 24, ta/2 = 1.711

  26. Interval Estimation of m 1-m 2:s 1 and s 2 Unknown 2.5 + 1.069 or 1.431 to 3.569 mpg We are 90% confident that the difference between the miles-per-gallon performances of M cars and J cars is 1.431 to 3.569 mpg.

  27. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown • Hypothesis Testing Left-tailed Right-tailed Two-tailed • Test Statistic

  28. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown Can we conclude, using a .05 level of significance, that the miles-per-gallon (mpg) performance of M cars is greater than the miles-per- gallon performance of J cars?

  29. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown 1. Develop the hypotheses. H0: 1 - 2= 0 Ha: 1 - 2 > 0 where: 1 = mean mpg for the population of M cars 2 = mean mpg for the population of J cars

  30. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown a = .05 2. Specify the level of significance. 3. Compute the value of the test statistic.

  31. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown • Using the p–Value Approach 4. Compute the p –value. Compute the thedegrees of freedom:

  32. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown • Using the Critical Value Approach 4. Determine the critical value and rejection rule. For a = .05 and df = 24, t.05 = 1.711

  33. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown • Using the Critical Value Approach 5. Compare the Test Statistic with the Critical Value. As t he test statistic 4.003 is greater than the Critical value 1.711, we reject H0. We are at least 95% confident that the miles-per-gallon (mpg) performance of M cars is greater than the miles-per-gallon performance of J cars?.

  34. Hypothesis Tests About m 1-m 2:s 1 and s 2 Unknown • Using the p-Value Approach 5. Compute the P-value and determine whether to reject H0. As the p–value <a = .05, we reject H0. We are at least 95% confident that the miles-per-gallon (mpg) performance of M cars is greater than the miles-per-gallon performance of J cars?.

  35. Inferences About the Difference BetweenTwo Population Means: Matched Samples • In a matched-sample design each sampled item provides a pair of data values. • This design often leads to a smaller sampling error • than the independent-sample design because • variation between sampled items is eliminated as a • source of sampling error.

  36. Inferences About the Difference BetweenTwo Population Means: Matched Samples • Example: A Chicago-based firm has documents that must be quickly distributed to district offices throughout the U.S. The firm must decide between two delivery services, UPX (United Parcel Express) and INTEX (International Express), to transport its documents.

  37. Inferences About the Difference BetweenTwo Population Means: Matched Samples In testing the delivery times of the two services, the firm sent two reports to a random sample of its district offices with one report carried by UPX and the other report carried by INTEX. Do the data on the next slide indicate a difference in mean delivery times for the two services? Use a .05 level of significance.

  38. Inferences About the Difference BetweenTwo Population Means: Matched Samples Delivery Time (Hours) District Office UPX INTEX Difference 32 30 19 16 15 18 14 10 7 16 25 24 15 15 13 15 15 8 9 11 7 6 4 1 2 3 -1 2 -2 5 Seattle Los Angeles Boston Cleveland New York Houston Atlanta St. Louis Milwaukee Denver

  39. Inferences About the Difference BetweenTwo Population Means: Matched Samples 1. Develop the hypotheses. H0: d = 0 Ha: d Let d = the mean of the difference values for the two delivery services for the population of district offices

  40. Inferences About the Difference BetweenTwo Population Means: Matched Samples a = .05 2. Specify the level of significance. 3. Compute the value of the test statistic.

  41. Inferences About the Difference BetweenTwo Population Means: Matched Samples • Using the Critical Value Approach 4. Determine the critical value and rejection rule. For a = .05 and df = 9, t.025 = 2.262. 5. Compare the Test Statistic with the Critical Value Because t = 2.94 > 2.262, we reject H0. We are at least 95% confident that there is a difference in mean delivery times for the two services?

  42. Inferences About the Difference BetweenTwo Population Means: Matched Samples • Using the p–Value Approach 4. Compute the p –value. For t = 2.94 and df = 9, the p–value is between .02 and .01. (This is a two-tailed test, so we double the upper-tail areas of .01 and .005.) 5. Determine whether to reject H0. Because p–value <a = .05, we reject H0. We are at least 95% confident that there is a difference in mean delivery times for the two services?

More Related