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1. A force of 10,000 N is applied to a stationary wall. How much work is performed?

1. A force of 10,000 N is applied to a stationary wall. How much work is performed?. W = F X D. 1. A force of 10,000 N is applied to a stationary wall. How much work is performed?. W = F X D. = 10,000 N X 0 m.

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1. A force of 10,000 N is applied to a stationary wall. How much work is performed?

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  1. 1. A force of 10,000 N is applied to a stationary wall. How much work is performed? W = F X D

  2. 1. A force of 10,000 N is applied to a stationary wall. How much work is performed? W = F X D = 10,000 N X 0 m

  3. 1. A force of 10,000 N is applied to a stationary wall. How much work is performed? W = F X D = 10,000 N X 0 m = 0 Nm

  4. 1. A force of 10,000 N is applied to a stationary wall. How much work is performed? W = F X D = 10,000 N X 0 m = 0 Nm = 0 J

  5. 2. A 950-N skydiver jumps from an altitude of 3000 m. What is the total work performed on the skydiver? W = F X D

  6. 2. A 950-N skydiver jumps from an altitude of 3000 m. What is the total work performed on the skydiver? W = F X D = 950 N X 3000 m

  7. 2. A 950-N skydiver jumps from an altitude of 3000 m. What is the total work performed on the skydiver? W = F X D = 950 N X 3000 m = 2,850,000 J

  8. 3. You are walking from your math class to your English class. You are carrying books that weigh 20 N. You walk 45 m down the hall, climb 15 meters up the stairs and then walk another 30 m to your English class. What is the total work done on the books? W = F X D

  9. 3. You are walking from your math class to your English class. You are carrying books that weigh 20 N. You walk 45 m down the hall, climb 15 meters up the stairs and then walk another 30 m to your English class. What is the total work done on the books? W = F X D = 20 N X 15 m

  10. 3. You are walking from your math class to your English class. You are carrying books that weigh 20 N. You walk 45 m down the hall, climb 15 meters up the stairs and then walk another 30 m to your English class. What is the total work done on the books? W = F X D = 20 N X 15 m = 300 J

  11. 4. How much work is done by a crane that lowers 1000 N of material a distance of 150 m? W = F X D

  12. 4. How much work is done by a crane that lowers 1000 N of material a distance of 150 m? W = F X D = 1000 N X 150 m

  13. 4. How much work is done by a crane that lowers 1000 N of material a distance of 150 m? W = F X D = 1000 N X 150 m = 150,000 J

  14. 5. A weightlifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? weight = M X 9.8 N kg

  15. 5. A weightlifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? weight = M X 9.8 N kg = 150 kg X 9.8 N kg

  16. 5. A weightlifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? weight = M X 9.8 N kg = 150 kg X 9.8 N kg = 1470 N

  17. 5. A weightlifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? W = F X D

  18. 5. A weightlifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? W = F X D = 1470 N X 0 m

  19. 5. A weightlifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? W = F X D = 1470 N X 0 m = 0 J

  20. 6. A 5 kg rock is lifted 2 m in 5 sec. How much work is done?

  21. 6. A 5 kg rock is lifted 2 m in 5 sec. How much work is done? weight = M X 9.8 N kg = 5 kg X 9.8 N kg = 49 N

  22. 6. A 5 kg rock is lifted 2 m in 5 sec. How much work is done? W = F X D

  23. 6. A 5 kg rock is lifted 2 m in 5 sec. How much work is done? W = F X D = 49 N X 2 m

  24. 6. A 5 kg rock is lifted 2 m in 5 sec. How much work is done? W = F X D = 49 N X 2 m = 98 J

  25. 7. A teacher pushed a 10-kg desk across a a floor for a distance of 5 m. She exerted a horizontal force of 20 N. How much work was done? W = F X D

  26. 7. A teacher pushed a 10-kg desk across a a floor for a distance of 5 m. She exerted a horizontal force of 20 N. How much work was done? W = F X D = 20 N X 5 m

  27. 7. A teacher pushed a 10-kg desk across a a floor for a distance of 5 m. She exerted a horizontal force of 20 N. How much work was done? W = F X D = 20 N X 5 m = 100 J

  28. 8. If 4,000 Nm are used to raise a 294 N object . How high is the mass raised? W = F X D

  29. 8. If 4,000 Nm are used to raise a 294 N object . How high is the mass raised? W = F X D 4,000 Nm= 294 N X D

  30. 8. If 4,000 Nm are used to raise a 294 N object . How high is the mass raised? W = F X D 4,000 Nm= 294 N X D 4,000 Nm= 294 N X D 294 N 294 N

  31. 8. If 4,000 Nm are used to raise a 294 N object . How high is the mass raised? W = F X D 4,000 Nm= 294 N X D 4,000 Nm= 294 N X D 294 N 294 N D = 13.6 m

  32. 8. Alternate solution D = W F D= 4000 Nm 294 N D = 13.6 m

  33. 9. A bulldozer performs 80,000 Nm of work pushing dirt a distance of 16 m. What is the force of the dirt? W = F X D

  34. 9. A bulldozer performs 80,000 Nm of work pushing dirt a distance of 16 m. What is the force of the dirt? W = F X D 80,000 Nm = F X 16 m

  35. 9. A bulldozer performs 80,000 Nm of work pushing dirt a distance of 16 m. What is the force of the dirt? W = F X D 80,000 Nm = F X 16 m 80,000 Nm = F X 16 m 16 m 16 m

  36. 9. A bulldozer performs 80,000 Nm of work pushing dirt a distance of 16 m. What is the force of the dirt? W = F X D 80,000 Nm = F X 16 m 80,000 Nm = F X 16 m 16 m 16 m F = 5,000 N

  37. F = W D 9. Alternate solution F= 80,000 Nm 16 m F = 5000 N

  38. 10. An ant does 1 N-m of work dragging a 0.0020-N grain of sugar. How far does the ant drag the sugar? W = F X D

  39. 10. An ant does 1 N-m of work dragging a 0.0020-N grain of sugar. How far does the ant drag the sugar? W = F X D 1 Nm= 0.0020 X D

  40. 10. An ant does 1 N-m of work dragging a 0.0020-N grain of sugar. How far does the ant drag the sugar? W = F X D 1 Nm= 0.0020 X D 1 Nm= 0.0020 N X D 0.0020 N 0.0020 N

  41. 10. An ant does 1 N-m of work dragging a 0.0020-N grain of sugar. How far does the ant drag the sugar? W = F X D 1 Nm= 0.0020 X D 1 Nm= 0.0020 N X D 0.0020 N 0.0020 N D = 500 m

  42. 10. Alternate solution D = W F D = 1 Nm 0.0020 N D = 500 m

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