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Explore the concepts of relative velocity and acceleration with examples and practice questions. Learn how to interpret and solve problems related to uniformly accelerated motion. Gain an understanding of the change in velocity over time intervals.
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Relative Velocity Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. • What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero • What is Mr. Fox’s velocity relative to Ms. Wood? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W] • What is Mr. Fox’s velocity relative to Ms. Rosebery? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W]
Relative Velocity Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. • What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero • What is Mr. Fox’s velocity relative to Ms. Wood? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W] • What is Mr. Fox’s velocity relative to Ms. Rosebery? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W]
Relative Velocity Ms. Rosebery is walking at 1 m/s [E]. Ms. Wood is walking at 1 m/s [W]. Mr. Fox is running at 4 m/s [W]. • What is Ms. Rosebery’s velocity relative to Ms. Wood? A. 1 m/s [E] B. 2 m/s [E] C. zero • What is Mr. Fox’s velocity relative to Ms. Wood? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W] • What is Mr. Fox’s velocity relative to Ms. Rosebery? A. 3 m/s [W] B. 4 m/s [W] C. 5 m/s [W]
An Introduction to Acceleration: Learning Goal • The student will interpret and solve example questions related to uniformly accelerated motion. (B3.2) Vocabulary: acceleration (B2.1)
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or:
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or:
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or:
Acceleration Acceleration is defined as the change in the velocity of an object per interval of time, or: v2 = final velocity and v1 = initial velocity
Acceleration Acceleration will have units of m/s/s or m/s2. (Notice also that acceleration is a vector.)
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration?
Example Jake increases his velocity from 13 m/s [E] to 25 m/s [E] in 5.0 s. What is his acceleration? His acceleration is 2.4 m/s2 [E].
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration?
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration?
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration?
Another Example Richard reduces his velocity from 15 m/s [forward] to 12 m/s [forward] in 4.0 s. What is his acceleration? His acceleration is 0.75 m/s2 [backward].
Rearranging the Equation The equation that represents the definition of acceleration may be rearranged to solve for any of the other variables, e.g.
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s?
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s?
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s?
Rearranging the Equation A ball is travelling at 12 m/s [up] and being accelerated at 9.8 m/s2 [down]. What is its velocity after 2.0 s? Its velocity is 7.6 m/s [down].
More Practice Homework: Acceleration Tomorrow: Acceleration Lab