1 / 18

Lecture 38

Lecture 38. CSE 331 Dec 5, 2012. OHs today (only online 9:30-11). Extra OH this week. Shortest Path Problem. Input: (Directed) Graph G=(V,E) and for every edge e has a cost c e (can be <0 ). t in V. Output: Shortest path from every s to t. Assume that G has no negative cycle.

pierson
Télécharger la présentation

Lecture 38

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Lecture 38 CSE 331 Dec 5, 2012

  2. OHs today (only online 9:30-11)

  3. Extra OH this week

  4. Shortest Path Problem Input: (Directed) Graph G=(V,E) and for every edge e has a cost ce (can be <0) t in V Output: Shortest path from every s to t Assume that G has no negative cycle 1 1 t s Shortest path has cost negative infinity 899 100 -1000

  5. When to use Dynamic Programming There are polynomially many sub-problems Richard Bellman Optimal solution can be computed from solutions to sub-problems There is an ordering among sub-problem that allows for iterative solution

  6. Recurrence Relation OPT(i,u) = cost of shortest path from u to t with at most i edges OPT(i,u) = min {OPT(i-1,u), min(u,w) in E{cu,w + OPT(i-1, w)}} Path uses ≤ i-1 edges Best path through all neighbors

  7. When to use Dynamic Programming There are polynomially many sub-problems Richard Bellman Optimal solution can be computed from solutions to sub-problems There is an ordering among sub-problem that allows for iterative solution

  8. Today’s agenda Finish Bellman-Ford algorithm Analyze the run time Group talk time: Natural order among OPT(i,u) values?

  9. The recurrence OPT(i,u) = shortest path from u to t with at most i edges OPT(i,u) = min {OPT(i-1,u), min(u,w) in E{cu,w + OPT(i-1, w)}}

  10. Some consequences OPT(i,u) = shortest path from u to t with at most i edges OPT(i,u) = min {OPT(i-1,u), min(u,w) in E{cu,w + OPT(i-1, w)}} OPT(n-1,u) is shortest path cost between u and t Group talk time: How to compute the shortest path between s and t given all OPT(i,u) values

  11. Longest path problem Given G, does there exist a simple path of length n-1 ?

  12. Longest vs Shortest Paths

  13. Two sides of the “same” coin Shortest Path problem Can be solved by a polynomial time algorithm Is there a longest path of length n-1? Given a path can verify in polynomial time if the answer is yes

  14. Poly time algo for longest path?

  15. P vs NP question P: problems that can be solved by poly time algorithms Is P=NP? NP: problems that have polynomial time verifiable witness to optimal solution Alternate NP definition: Guess witness and verify!

  16. Proving P ≠ NP Pick any one problem in NP and show it cannot be solved in poly time Pretty much all known proof techniques provably will not work

  17. Proving P = NP Will make cryptography collapse Compute the encryption key! Prove that all problems in NP can be solved by polynomial time algorithms Solving any ONE problem in here in poly time will prove P=NP! NP NP-complete problems

  18. If you are curious for more CSE431: Algorithms CSE 396: Theory of Computation

More Related