SlideServe
Menu
Préférences
© SlideServe · v2026

Chapter 15 Chemical Equilibrium

platt avatar
26 diapositives · 569 Views · Jul 26, 2014

Chapter 15 Chemical Equilibrium. BLB 12 th. 2 NO 2 (g) → 2 NO(g) + O 2 (g). ⇌. N 2 O 4 ( g ) colorless. 2 NO 2 ( g ) brown. 15.1 The Concept of Equilibrium. Chemical equilibrium occurs when a reaction and its reverse reaction proceed at the same rate. ⇌. N 2 O 4 ( g ). 2 NO 2 ( g ).

Chapter 15 Chemical Equilibrium - slide 1
01 / 26Chapter 15 Chemical Equilibrium
1 / 17

Télécharger la présentation

Chapter 15 Chemical Equilibrium
Une image / un lien ci-dessous est fourni (tel quel) pour télécharger la présentation

Politique de téléchargement : le contenu du site vous est fourni TEL QUEL pour votre information et votre usage personnel ; il ne peut être vendu, concédé sous licence ni partagé sur d’autres sites sans l’accord de son auteur.Le contenu vous est fourni TEL QUEL, pour votre information et votre usage personnel uniquement. Téléchargez la présentation en cliquant sur ce lien. Lors du téléchargement, si vous ne parvenez pas à télécharger une présentation, l’éditeur a peut-être supprimé le fichier de son serveur.Pendant le téléchargement, si vous ne parvenez pas à obtenir une présentation, le fichier a peut-être été supprimé par l’éditeur.

F I N

Plus de contenu associé

Transcription de la présentation
  1. Chapter 15Chemical Equilibrium BLB 12th

  2. 2 NO2(g) → 2 NO(g) + O2(g)

  3. ⇌ N2O4(g) colorless 2 NO2(g) brown 15.1 The Concept of Equilibrium Chemical equilibrium occurs when a reaction and its reverse reaction proceed at the same rate.

  4. ⇌ N2O4(g) 2 NO2(g) The Concept of Equilibrium • As a system approaches equilibrium, both the forward and reverse reactions are occurring. • At equilibrium, the forward and reverse reactions are proceeding at the same rate.

  5. ⇌ N2O4(g) 2 NO2(g) A System at Equilibrium • Once equilibrium is achieved, the concen-trations of reactants and products remain constant. • Ratio of concentration values equals a constant.

  6. The Concept of Equilibrium • The reaction system is closed. • Opposing reactions occur at equal rates, that is, the rates of forward and reverse reactions are equal. • Dynamic process (never stops) • Concentrations of reactants and products are constant. • Equilibrium can be reached from either direction, reactants or products.

  7. 15.2 The Equilibrium Constant aA + bB ⇌ cC + dD

  8. 15.2 The Equilibrium Constant • Kis constant for a reaction, regardless of the [A]0. • K is temperature dependent. • K depends on stoichiometry, not on the mechanism. • Pure solid or liquid reactant & products are not included for heterogeneous equilibria. (15.4, p. 623) • Water (or other pure solvent) is not included if the reactant and product concentrations are low. (p. 625) • Kc – concentrations (M) of solutions • Kp – partial pressures of gases; p. 617 to convert betweenKp &Kc

  9. Write the expression for K. • N2(g) +O2(g) ⇌ 2 NO(g) • 2 SO2(g) + O2(g) ⇌ 2 SO3(g)

  10. ⇌ N2O4(g) 2 NO2(g) Evaluating K

  11. 15.3 Understanding and Working with Equilibrium Constants The Magnitude of K • K >> 1 Essentially all products; lies to right K > 1 product-favored K < 1 reactant-favored K << 1 Essentially all reactants; lies to left

  12. Manipulating K (pp. 620-622) • Reverse reaction: • Adding reactions: • Multiplying reaction by some factor: #1: C(s) + ½ O2(g) ⇌ CO(g) #2: 2 C(s) + O2(g) ⇌ 2 CO(g)

  13. 15.4 Heterogeneous Equilibria • Reactant components are in different phases. • When a pure solid or liquid is involved in a heterogeneous equilibrium, its concentration is not included in the K expression. • The concentration of a pure solid or pure liquid doesn’t change. • Write the K expression: SnO2(s) +2 CO(g) ⇌ Sn(s) + 2 CO2(g)

  14. 15.5 Calculating Equilibrium Constants • Must plug in the equilibrium concentrations of reactants and products • A concentration table with initial, change, and equilibrium concentrations is set up. • See Sample Exercise 15.9. • More in lab and in Chapter 16 with weak acids and bases.

  15. Calculating K N2(g) + 3 H2(g) ⇌ 2 NH3(g) p. 642 @ 472°C 2.46 7.38 0.166 ← eq. partial pressures (atm)

  16. 15.6 Applications of Equilibrium Constants • Predicting the direction a reaction must proceed to establish equilibrium • The reaction quotient, Q (p. 627) • Q has the same form as K, but for non-equilibrium conditions. • Comparing Q and K: Q < K achieves equilibrium by shifting to right Q = K @ equilibrium Q > K achieves equilibrium by shifting to left

  17. Sample problem 46a N2(g) + 3 H2(g) ⇌ 2 NH3(g) KP= 4.51 x 10-5 at 450°C 45 atm55 atm 98 atm

  18. 15.7 Le Châtelier’s Principle If a system at equilibrium is disturbed by a change in concentration, pressure, or temperature, the system will shift its equilibrium position to counter the effect of the disturbance. (p. 631)

  19. N2(g) + 3 H2(g) ⇌ 2 NH3(g)

  20. Le Châtelier’s Principle

  21. ⇌ N2O4(g) 2 NO2(g)

  22. ⇌ N2O4(g) colorless 2 NO2(g) brown 15.1 The Concept of Equilibrium Chemical equilibrium occurs when a reaction and its reverse reaction proceed at the same rate.

  23. Sample problem 61 2 SO2(g) + O2(g) ⇌ 2 SO3(g) ΔH < 0 Effect on equilibrium mixture when… (a) O2(g) is added? (b) the reaction mixture is heated? (c) the volume of container is doubled? (d) a catalyst is added? (e) the total P is increased by adding a noble gas? (f) SO3(g) is removed?

  24. 6 CO2(g) + 6 H2O(l) ⇌ C6H12O6(s) + 6 O2(g) ΔH = 2816 kJ Write the K expression. Effect on equilibrium mixture when… (a) PCO2 is increased? (b) the reaction is heated? (c) some CO2(g) is removed? (d) the total P is decreased? (e) part of C6H12O6(s) is removed? (f) a catalyst is added?