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10-2-13 Bellwork

10-2-13 Bellwork. Bellwork solutions. Lesson 2-6 (Intro to Functions) Objectives: The student will be able to:. 1. To determine if a relation is a function. 2. To find the value of a function. Functions.

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10-2-13 Bellwork

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  1. 10-2-13 Bellwork

  2. Bellwork solutions

  3. Lesson 2-6 (Intro to Functions)Objectives:The student will be able to: 1. To determine if a relation is a function. 2. To find the value of a function.

  4. Functions A function is a relation in which each element of the domain is paired with exactly one element of the range. Another way of saying it is that there is one and only one output (y) with each input (x). f(x) y x

  5. Function Notation Input Name of Function Output

  6. 2 3 5 4 3 0 2 3 f(x) f(x) f(x) f(x) Determine whether each relation is a function. 1. {(2, 3), (3, 0), (5, 2), (4, 3)} YES, every domain is different!

  7. 1 4 5 5 6 6 9 3 1 2 f(x) f(x) f(x) f(x) f(x) Determine whether the relation is a function. NO, 5 is paired with 2 numbers! 2. {(4, 1), (5, 2), (5, 3), (6, 6), (1, 9)}

  8. Answer Now Is this relation a function?{(1,3), (2,3), (3,3)} • Yes • No

  9. Vertical Line Test (pencil test) If any vertical line passes through more than one point of the graph, then that relation is not a function. Are these functions? FUNCTION! FUNCTION! NOPE!

  10. Vertical Line Test FUNCTION! NO! NO WAY! FUNCTION!

  11. Answer Now Is this a graph of a function? • Yes • No

  12. Given f(x) = 3x - 2, find: = 7 1) f(3) 2) f(-2) 3(3)-2 3 7 = -8 3(-2)-2 -2 -8

  13. Given h(z) = z2 - 4z + 9, find h(-3) (-3)2-4(-3)+9 -3 30 9 + 12 + 9 h(-3) = 30

  14. Answer Now Given g(x) = x2 – 2, find g(4) • 2 • 6 • 14 • 18

  15. Answer Now Given f(x) = 2x + 1, find-4[f(3) – f(1)] • -40 • -16 • -8 • 4

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