1 / 11

Algebra Readiness

Algebra Readiness. Chapter 4 Section 5. 4.5: Divide Integers. The mean , also called the average , is the sum of the numbers in a set of data divided by the number of items in the set.

randall-baxter
Télécharger la présentation

Algebra Readiness

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Algebra Readiness Chapter 4 Section 5

  2. 4.5: Divide Integers The mean, also called the average, is the sum of the numbers in a set of data divided by the number of items in the set. The average rate of change of one quantity with respect to another is the change of the first quantity divided by the change in the second quantity.

  3. Dividing Integers * The quotient of two integers with the same sign is positive. * The quotient of two integers with different signs is negative. * The quotient of 0 and any nonzero integer is 0.

  4. 36 = 3 Same sign, so quotient is positive. 12 – 56 = b. – 7 Different signs, so quotient is negative. 8 45 = c. – 5 Different signs, so quotient is negative. – 9 0 The quotient of zero and any nonzero integer is 0. = d. 0 – 18 Example 1 Dividing Integers – a. –

  5. ( – ) ( – ) ( – ) 21 53 46 32 14 + + + + = Mean Write sum divided by 5. 5 – 60 = Add. 5 = – 12 Divide. The mean of the numbers is 12. ANSWER – Example 2 Finding a Mean Find the mean of the numbers: 21, –53, –46, 32, –14.

  6. Practice for Examples 1 and 2 ANSWER 58 38 2. ANSWER – 19 – 2 – 72 3. ANSWER – 12 6 0 4. ANSWER 0 – 9 Find the quotient. – 58 1. – 1

  7. Practice for Examples 1 and 2 ANSWER –7 ANSWER 2 Find the mean of the numbers. 5. 25, –26, –25, 46, –55 6. –3, 0, 4, 5, –2, 8

  8. Month Temp. (°F) November 5 – December 5 – January 7 – February 10 – SOLUTION March 7 April 6 ( – ) ( – ) ( – ) ( – ) + + + + + 5 5 7 10 7 6 = Mean 6 – 18 = 6 = – 3 The mean high temperature is 3°F. ANSWER – Example 3 Finding the Mean of Data The table shows the average monthly high temperature for the coldest months in Barrow, Alaska. What is the mean high temperature for these months?

  9. Practice for Example 3 ANSWER 10°F • At McMurdo Base in Antarctica, the average monthly • temperatures for January through April are 27°F, 16°F, 1°F, and –4°F. What is the mean average temperature for those months?

  10. SOLUTION To find the change in altitude, subtract the starting altitude from the ending altitude. = – – 616 1500 884 = – 884 ft – 26 ft/min 34 min Example 4 Finding the Average Rate of Change A hot air balloon flying at an altitude of 1500 feet descended to an altitude of 616 feet in 34 minutes. What was the average rate of change in altitude in feet per minute? Divide by the time it took the balloon to descend to find the rate of change.

  11. Practice for Example 4 ANSWER 30 ft/min • A scuba diver swimming at an elevation of –105 feet • relative to the surface of the water rises to an elevation of –15 feet in 3 minutes. What is the average rate of change in the diver’s elevation in feet per minute?

More Related