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Expanding Square Search Pattern

Expanding Square Search Pattern. HEY! I’M OVER HERE !!!. Expanding Square Search. Characteristics: Used in relatively small search areas There is a good starting point Provides uniform coverage. Criteria:. Expanding Square Search. Search Area. Search Pattern.

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Expanding Square Search Pattern

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  1. Expanding Square Search Pattern HEY! I’M OVER HERE !!!

  2. Expanding Square Search • Characteristics: • Used in relatively small search areas • There is a good starting point • Provides uniform coverage Criteria:

  3. Expanding Square Search Search Area Search Pattern How do we do that ????

  4. We use our: Expanding Square Search Pattern Plotting Aid

  5. Expanding Square Search Execution: • Commence Search Point is at datum (provided by SAR Mission Coordinator) • First leg is down drift • All turns are 90 degrees to the right • Search leg length is increased byone track spaceon every other leg.

  6. Expanding Square Search The Search and Rescue Mission Coordinator (SMC) provides: • Commence Search Point (CSP) • Where you begin • Lat and Lon

  7. Expanding Square Search • Begin your search at theCommence Search Point – CSP • This is provided by SAR Mission Coordinator (SMC) Lat xx° xx.x’ Long xxx° xx.x’

  8. Expanding Square Search SMC also provides: • Track Spacing (separation) • This will be the distance between parallel search tracks • This also happens to be the length of the first leg of the search

  9. The SMC provides Track Spacing • Track Spacing also equals the length of Leg 1 of the search Expanding Square Search For example: ½ mile

  10. Expanding Square Search To begin your search you need to: • Determine the constant speed at which you will run your vessel during the search • Calculate the time to run the first leg of your search based on this constant speed

  11. Expanding Square Search • Using your search plotting aid, calculate the time for running the first leg based on the distance of the Track Spacing and the speed you will go For example: If I run the search at 5 knots, how much time must I run to go ½ mile? ½ mile You can use your plotting aid to get the answer

  12. Speed is how fast your boat will run during the search The intersection indicates how many minutes you will run the first search leg.In our example this is 6 minutes. Nautical Miles is the Track Spacing given by the SMC

  13. Expanding Square Search • You will need to remember (write down) the time you calculated to run the first leg • We will call the value of the initial leg run time by the name “X” • The value of X will be used in conjunction with your plotting aid to determine the length of time to run all future legs of the search • In our example, X is 6 minutes

  14. Expanding Square Search • The heading of your initial search leg will be with the current In our example: 000°

  15. Rotate the dial on your plotter until the arrow for LEG 1 is pointing to the heading that the current is flowing This will be your initial heading In our example this is 000°

  16. 90° Expanding Square Search • Run the first leg of your search for the initial time and at the speed you calculated In our example, 6 minutes at 5 knots heading 000° • At the end of your calculated time, turn right 90 ° (all turns are 90° to the right) 1 • Use your plotting aid to find your new heading and the time to run for this next leg

  17. And carrying it down to the parallel line that passes through the center of the dial Follow this line out to the edge of the dial to get your course heading The heading you should follow on the next leg is found by taking the number of the leg you will be on; in this case Leg 2 In our example, the heading for Leg 2 is 90 °

  18. Follow the line on the plotter for the new leg (in this case Leg 2) back toward the center of the dial until you see a number in front of the letter X The time you should stay on this new heading must be calculated by multiplying X (Leg 1 run time) times a multiplier shown on the plotter

  19. This is the number you multiply times your value for X to determine the length of the run time for this leg In the case of Leg 2, the number in front of X is 1. So the run time for Leg 2 = 1 *X In our example the run time for Leg 2 is : 1 *6 minutes = 6 minutes

  20. Expanding Square Search • Run Leg 2 for the time you calculated at your constant speed and on the heading you determined from your plotting aid In our example, 6 minutes at 5 knots heading 090° 2 1

  21. Expanding Square Search • Run Leg 2 for the time you calculated at your constant speed and on the heading you determined from your plotting aid 2 • At the end of your calculated time, turn right 90 ° 1 • Use your plotting aid to find your new heading and time to run for this next leg

  22. And carrying it across to the parallel line that passes through the center of the dial Follow this line out to the edge of the dial to get your course heading In our example, the heading for Leg 3 is 180 ° The heading you should follow on the next leg is found by taking the number of the leg you will be on; in this case Leg 3

  23. Follow the line on the plotter for the new leg (in this case Leg 3) back toward the center of the dial until you see a number in front of the letter X The time you should stay on this new heading must be calculated by multiplying X (Leg 1 run time) times the multiplier shown on the plotter

  24. In the case of Leg 3, the number in front of X is 2. So the run time for Leg 3 = 2 *X This is the number you multiply times your value for X to determine the length of the run time for this leg In our example the run time for Leg 3 is : 2 * 6minutes = 12 minutes

  25. Expanding Square Search • Run Leg 3 for the time you calculated at your constant speed and on the heading you determined from your plotting aid In our example, 12 minutes at 5 knots heading 180° 2 1 3

  26. Expanding Square Search • Run Leg 3 for the time you calculated at your constant speed and on the heading you determined from your plotting aid 2 • At the end of your calculated time, turn right 90 ° 1 3 • Use your plotting aid to find your new heading and time to run for this next leg

  27. The heading you should follow on the next leg is found by taking the number of the leg you will be on; in this case Leg 4 And carrying it to the parallel line that passes through the center of the dial Follow this line out to the edge of the dial to get your course heading In our example, the heading for Leg 4 is 270 °

  28. Follow the line on the plotter for the new leg (in this case Leg 4) back toward the center of the dial until you see a number in front of the letter X The time you should stay on this new heading must be calculated by multiplying X times the multiplier shown on the plotter

  29. In the case of Leg 4, the number in front of X is 2. So the run time for Leg 4 = 2 * X This is the number you multiply times your value for X to determine the length of the run time for this leg In our example the run time for Leg 4 is : 2 * 6 minutes = 12 minutes

  30. Expanding Square Search • Run Leg 4 for the time you calculated at your constant speed and on the heading you determined from your plotting aid In our example, 12 minutes at 5 knots heading 270° 2 1 3 4

  31. Expanding Square Search • Run Leg 4 for the time you calculated at your constant speed and on the heading you determined from your plotting aid 2 • At the end of your calculated time, turn right 90 ° 1 3 • Use your plotting aid to find your new heading and time to run for this next leg 4

  32. The heading you should follow on the next leg is found by taking the number of the leg you will be on; in this case Leg 5 And carrying it to the parallel line that passes through the center of the dial Follow this line out to the edge of the dial to get your course heading In our example, the heading for Leg 5 is 000 °

  33. Follow the line on the plotter for the new leg (in this case Leg 5) back toward the center of the dial until you see a number in front of the letter X The time you should stay on this new heading must be calculated by multiplying X by the multiplier shown on the plotter

  34. In the case of Leg 5, the number in front of X is 3. So the run time for Leg 5 = 3 *X This is the number you multiply times your value for X to determine the length of the run time for this leg In our example the run time for Leg 5 is : 3 *6minutes = 18 minutes

  35. Expanding Square Search • Run Leg 5 for the time you calculated at your constant speed and on the heading you determined from your plotting aid In our example, 18 minutes at 5 knots heading 000° 2 5 1 3 4

  36. Expanding Square Search • Run Leg 5 for the time you calculated at your constant speed and on the heading you determined from your plotting aid 2 • At the end of your calculated time, turn right 90 ° 5 1 3 • Use your plotting aid to find your new heading and time to run for this next leg 4

  37. Expanding Square Search • Continue to use your search plotter to determine the heading and time to run for each subsequent leg of the search 6 2 5 1 3 7 4 8

  38. Expanding Square Search • The time to run a search leg is increased by the time to run one track space after every two legs 18 6 • In our example the time to run one track space is six minutes 18 6 12 24 12 24

  39. ANY QUESTIONS? SAR PATTERNS

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