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498 1905 kj mol - PowerPoint PPT Presentation

Example Problem: TBE

Example Problem: TBE. Determine the enthalpy change that accompanies the reaction below. Use the method of average bond dissociation energies to determine the answer 4 x 414 + 0.5 x 498 = 1905 kJ/mol for bonds broken (this always costs energy, +ve sign)

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498 1905 kj mol - PowerPoint PPT Presentation

Example Problem: TBE