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Reverse ys reverse xs - PowerPoint PPT Presentation

Proof: A |? C -- lemma :/++

Proof: A |? C -- lemma :/++. ++:: [t] -> [t] -> [t] [] ++ y = y (x:xs) ++ y = x:(xs ++ y). (1) (2). da ++ A:. segue C:. (x:xs) ++ y = [x]++(xs ++ y). Lemma:/++. Proof: ( riduzione di termini uguali ) (x:zs) ++ ys = x:(zs++y) -- (2) ma, per ogni w:

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Reverse ys reverse xs - PowerPoint PPT Presentation

Proof: A |? C -- lemma :/++