1 / 11

Warm Up - 2/15 on page 50

Warm Up - 2/15 on page 50. What is kept constant in Boyle ’ s Law? Solve for the unknown: P 1 = 0.456 atm V 1 = 289 mL P 2 = 0.287 atm V 2 = ???. Gay-Lussac ’ s Law. Gay-Lussac ’ s Law. Created by Joseph Gay-Lussac

shea
Télécharger la présentation

Warm Up - 2/15 on page 50

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Warm Up - 2/15 on page 50 • What is kept constant in Boyle’s Law? • Solve for the unknown: • P1 = 0.456 atm • V1 = 289 mL • P2 = 0.287 atm • V2 = ???

  2. Gay-Lussac’s Law

  3. Gay-Lussac’s Law • Created by Joseph Gay-Lussac • Deals with changes in pressure and temperature (volume kept constant) • As one increases, the other increases as well (direct relationship)

  4. Formula • P1 = P2 • T1 T2

  5. Example • At 120°C, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 205°C? • P1 = 1.07 atm • T1 = 120°C • P2 = ??? • T2 = 205°C

  6. Example • (1.07 atm) = P2 • (120°C) (205°C) • (1.07 atm)*(205°C) = P2 • (120°C) • P2 = 1.80 atm

  7. Charles’ Law

  8. Charles’ Law • Created by Jacques Charles • Deals with changes in volume and temperature (pressure kept constant) • As one increases, the other increases as well (direct relationship)

  9. Formula • V1 = V2 • T1 T2

  10. Example • A gas at 65°C occupies 4.22 L. At what Celsius temperature will the volume be 3.87 L? • V1 = 4.22 L • T1 = 65°C • V2 = 3.87 L • T2 = ???

  11. Example • (4.22 L) = (3.87 L) • (65°C) T2 • (4.22 L)*T2 = (3.87 L)*(65°C) • T2 = (3.87 L)*(65°C) = 59.6°C • (4.22 L)

More Related