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Blue Lotus. A ptitude - TCS. Problems on Numbers. A car is filled with 4 ¼ gallons of oil for full round trip. Fuel is taken 1/4 gallon more while going down than coming up. What is the fuel consumed in coming up?. Problems on Numbers.

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## Blue Lotus

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**Blue Lotus**Aptitude - TCS**Problems on Numbers**A car is filled with 4 ¼ gallons of oil for full round trip. Fuel is taken 1/4 gallon more while going down than coming up. What is the fuel consumed in coming up?**Problems on Numbers**Let ‘X’ be the quantity of fuel consumed for the trip in one directionThe fuel consumed while going = X + ¼ The fuel consumed while coming = XTherefore, the fuel consumed for the trip = (X + ¼) + X = 4 ½ 2X + ¼ = 4 ½ => 2X = 4 ½ - ¼ => 2X = 4 ¼ => X= 2 gallons approx**Problems on Numbers**A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there?**Problem on Numbers**The cost of 1 pencil, 2 pens and 4 erasers is Rs. 22, while the cost of five pencils, four pens and two eraser is 32. how much will 3 pencils, 3 pens and 3 eraser? (TCS)**Problem on Numbers**Solution: Let Pencil be x, Pens be y, Erasers be z x + 2y + 4z = 22 5x + 4y + 2z = 32 Adding we get 6x+6y+6z = 54 3x + 3y + 3z = 27 3 Pencil, 3 Pens and 3 Eraser is Rs. 27.**Problem on Numbers**If the numerator of a fraction is increased by 25% and denominator decrease by 20%, the new value is 5/4. what is the original value? (TCS)**Problem on Numbers**Solution: ( x + 25x/100) / (y – 20y/100) = 5/4 125x / 80y = 5/4 x/y = 5/4 * 80/ 125 = 4/5**Puzzle**In 80 coins one coin is counterfiet. What is the minimum number of weighings to find out counterfiet coin? (TCS)**Puzzle**SIX**Puzzle**In a well of 20feet depth, a frog jumps 5feet up in the morning and comes 4feet down in the evening,on which day the frog gets out of the well.**Puzzle**Sixteen**Number System**The number 362 in decimal system is given by (1362)x in the X system of numbers. find the value of X.**Number System**In which of the system, decimal number 184 is equal to 1234?**Number System**Find the value of the 678 to the base 7.**Number System**1656**Number System**The base 5 representation of the decimal number 2048 is _____.**Odd Man Out**a)LINUX b) WINDOWS 98 c)SOLARIS d) SMTP a)JAVA b) LISP c) Smaltalk d) Eiffle**Odd Man Out**1.HTTP 2.ARP 3.SNMP 4.SAP 1.Linux 2.windows NT 3.sql server 4.Unix**Problems on Ages**Father’s age is 5 times his son's age.4 years back the father was 9 times older than his son. Find the father's present age? (TCS)**Problems on Ages**Solution: F = 5S F – 4 = 9(S-4) F – 5s = 0 F – 9S = -36 + 4 = -32 4S = 32 S = 8 Father age = 40 years**Problems on Ages**One year ago Pandit was three times his sister’s age. Next year he will be only twice her age. How old will Pandit be after five years? (TCS)**Problems on Ages**Solution: (P-1) = 3(S -1) P + 1 = 2( s+1) P – 3S = -3 + 2 = -2 P – 2S = 2-1 = 1 S = 3 P – 3(3) = -2 P – 9 = -2 P = -2 + 9 = 7 After 5 years = 12**Problems on Ages**A father is three times as old as his son after 15 years the father will be twice as old as his son’s age at that time. What is the father’s present age ? (TCS)**Problems on Ages**Solution: F = 3S F + 15 = 2(S +15) Father’s age = 45, Son’s age = 15**Alligation or Mixture**• (Quantity of cheaper / Quantity of costlier) (C.P. of costlier) – (Mean price) = -------------------------------------- (Mean price) – (C.P. of cheaper)**Alligation or Mixture**Cost of Cheaper Cost of costlier c d Cost of Mixture m d-m m-c (Cheaper quantity) : (Costlier quantity) = (d – m) : (m – c)**Alligation or Mixture**A merchant has 100 kg of salt, part of which he sells at 7% profit and the rest at 17% profit. He gains 10% on the whole. Find the quantity sold at 17% profit?**Alligation or Mixture**Solution: 7 17 10 (17-10) (10-7) 7 : 3 The ratio is 7:3 The quantity of 2nd kind = 3/10 of 100kg = 30kg**Alligation or Mixture**A 3-gallon mixture contains one part of S and two parts of R. In order to change it to mixture containing 25% S how much R should be added? (TCS)**Alligation or Mixture**Answer: R : S 2 : 1 75% : 25% 3 : 1 1 gallon of R should be added.**Alligation or Mixture**In two varieties of tea, one costing Rs. 25/kg. and the other costing RS. 30/kg are blended to produce blended variety of tea in ratio 2:3. find the cost price of the mixture ?**Alligation or Mixture**Solution: 25 30 x (30- 28) (28-25) 2 : 3 Let mixed price be x If you subtract 28 from 30 you will get 2 and if you subtract 25 from 28 you will get 3.**Chain Rule**Direct Proportion : A B A B Indirect Proportion: A B A B**Chain Rule**A can copy 50 papers in 10 hours while both A & B can copy 70 papers in 10 hours. Then how many hours are required for B to copy 26 papers? (TCS)**Chain Rule**A stationary engine has enough fuel to run 12 hours when its tank is 4/5 full. How long will it run when the tank is 1/3 full? TCS Question**Chain Rule**Answer: Tank hours 4/5 12 1/3 x 4/5 x = 12 * 1/3 It will run for 5 hours**Partnership**Types: • A invested Rs.x and B invested Rs.y then A:B = x : y • A invested Rs. x and after 3 months B invested Rs. y then the share is • A:B = x * 12 : y * 9**Share**A sum of money is divided among A, B, C such that for each rupee A gets, B gets 65 paise and c gets 35 paise if c’s share is Rs. 560. what is the sum? TCS**Partnership**Solution A : B : C 100 : 65 : 35 20 : 13 : 7 Total = 20+13+7 = 40 C’ share = 560 7/40 *X =560 X= 3200**Share**If Rs. 1260 is divided among A, B, C in the ratio 2 : 3 : 4 what is C’s share? TCS**Ratio and Proportion**Solution: C’s Share = 4/9*1260 C’s share = Rs. 560**Time and Work**• If A can do a piece of work in n days, • then A’s 1 day’s work = 1/n • If A is thrice as B, then: Ratio of work done by A and B = 3:1**Pipes and Cisterns**• P1 fills in x hrs. Then part filled in 1 hr is 1/x • P2 empties in y hrs. Then part emptied in 1 hr is 1/y**Pipes and Cisterns**• P1 and P2 both working simultaneously which fills in x hrs and empties in y hrs resp ( y>x) then net part filled is 1/x – 1/y • P1 can fill a tank in X hours and P2 can empty the full tank in y hours( where x>y), then on opening both pipes, the net part empties in hour 1/y -1/x**Time and Work**One fast typist types same matter in 2 hours and another slow typist types the same matter in 3 hours. If both do combine in how much time will they finish? TCS Question**Time and Work**Solution: Fast typist = 1/2 ; slow typist = 1/3 ; Together: = 1/2 + 1/3 = 5/6 so 6/5 hrs The work will be completed in 6/5 Hrs.**Time and Work**A and B can finish a piece of work in 30 days, B and C in 40 days, while C and A in 60 days .In how many days A, B and C together can finish the work ?

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