1 / 11

Calculating Gas Volume and Stoichiometry in Chemical Reactions

This guide covers the calculation of the volume of gases in various conditions using the Ideal Gas Law and stoichiometry. We explore how to find the volume of (O_2) at given temperature and pressure, as well as determining the volume of (CO_2) produced from a reaction involving (CaCO_3). Additionally, we analyze how many grams of (Al_2O_3) can be formed from a set volume of (O_2) under specified conditions. The content aims to facilitate understanding of gas behavior and reaction stoichiometry.

shiro
Télécharger la présentation

Calculating Gas Volume and Stoichiometry in Chemical Reactions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Bellwork: What is the volume, in liters, of 0.250 mol of oxygen gas at 20.0ºC and 0.974 atm pressure? V = ? n = 0.250 mol T = 20ºC + 273 = 293 K P = 0.947 atm PV = nRT 6.17 L O2 = nRT P 0.250 mol (.0821 L·atm/mol·K) (293 K) 0.947 atm V = =

  2. Ch. 11 - Gases IV. Gas Stoichiometry

  3. Gas Stoichiometry • Moles  Liters of a Gas: • STP - use 22.4 L/mol • Non-STP - use ideal gas law • Non-STP • Given liters of gas? • start with ideal gas law • Looking for liters of gas? • start with stoichiometry conv.

  4. Gas Stoichiometry Problem • What volume of CO2 forms from 5.25 g of CaCO3 at 103 kPa & 25ºC? CaCO3 CaO + CO2 5.25 g ? Lnon-STP Looking for liters: Start with stoich and calculate moles of CO2. 5.25 g CaCO3 1 mol CaCO3 100.09g CaCO3 1 mol CO2 1 mol CaCO3 = 0.0525 mol CO2 Plug this into the Ideal Gas Law to find liters.

  5. Gas Stoichiometry Problem • What volume of CO2 forms from 5.25 g of CaCO3 at 103 kPa & 25ºC? GIVEN: P=103 kPa V = ? n=0.0525 mol T=25°C = 298 K R=8.315LkPa/molK WORK: PV = nRT V = nRT/P V=(0.0525mol)(8.315LkPa/molK)(298K) (103 kPa) V = 1.26 L CO2

  6. Gas Stoichiometry Problem • How many grams of Al2O3 are formed from 15.0 L of O2 at 97.3 kPa & 21°C? 4 Al + 3 O2 2 Al2O3 15.0 L non-STP ? g GIVEN: P=97.3 kPa V = 15.0 L n=? T=21°C = 294 K R=8.315LkPa/molK WORK: PV = nRT n = PV/RT n= (97.3 kPa) (15.0 L) (8.315LkPa/molK) (294K) n = 0.597 mol O2 Given liters: Start with Ideal Gas Law and calculate moles of O2. NEXT 

  7. Gas Stoichiometry Problem • How many grams of Al2O3 are formed from 15.0 L of O2 at 97.3 kPa & 21°C? 4 Al + 3 O2 2 Al2O3 15.0L non-STP ? g Use stoich to convert moles of O2 to grams Al2O3. 0.597 mol O2 2 mol Al2O3 3 mol O2 101.96 g Al2O3 1 mol Al2O3 = 40.6 g Al2O3

More Related