1 / 9

5.8 Solving Quadratic Funtions by Completing the Square

5.8 Solving Quadratic Funtions by Completing the Square. 1/28/2013. Vocabulary. Whenever you multiply a binomial by itself, the resulting trinomial is called a perfect square trinomial. Perfect Square Trinomial:. Example:. This is the area of this square. x+1. x+1. Vocabulary.

shona
Télécharger la présentation

5.8 Solving Quadratic Funtions by Completing the Square

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 5.8 Solving Quadratic Funtions by Completing the Square 1/28/2013

  2. Vocabulary Whenever you multiply a binomial by itself, the resulting trinomial is called a perfect square trinomial Perfect Square Trinomial: Example: This is the area of this square x+1 x+1

  3. Vocabulary The process of adding a constant c to the expression x2 + bx to make it a perfect square trinomial (PST) Completing the Square : How? By adding to x2 + bx What is it used for: Converting equations from standard form to vertex form. To solve quadratic functions when “Big X” does not work! Factored form of PST: The square of 2 binomials

  4. Review Equation of a Parabola in VERTEX FORM: Where (h, k) is the vertex

  5. Steps for completing the square Standard form : y = x2 + bx + c y = x2 + bx + c ( ) This is a PST y = (x2 + bx+ + c - Factored form of PST: • Put ( ) around x2 + bx and move c outside ( ) • Take half of b and square it. Add it to the ( ) and subtract it from c. • 3. Factor the PST in ( ) and simplify c - y = (x + 2 + d Note: if y = x2–bx + c Then y = (x -)2 + d

  6. Example 1 Rewrite y = x2 + 6x + 5 in Vertex Form and determine the vertex. y = x2 + 6x ( ) + 5 • Put ( ) around x2 + 6x and move +5 outside ( ) • Take half of 6 and square it. Add 9 to the ( ) and subtract 9 from 5. • 3. Factor the PST in ( ) and simplify This is a PST y = (x2 + 6x + + 5 - Factored form of PST: y = (x + 2 - 4 Vertex (-3, -4)

  7. Example 2 Rewrite y = x2- 6x + 10 in Vertex Form and determine the vertex. y = x2- 6x ( ) + 10 • Put ( ) around x2 - 6x and move +10 outside ( ) • Take half of 6 and square it. Add 9 to the ( ) and subtract 9 from 10. • 3. Rewrite what’s in the ( ) as (x - 3)2 y = (x2- 6x + + 10 - y = (x -2 + 1 Vertex (3, 1)

  8. Checkpoint ANSWER ( )2 – + y 3; x 4 = ( ) 4, 3 – y x2 8x + 19 = Use Completing the Square Write in vertex form. Then identify the vertex.

  9. Homework: 5.8 p.271 #15-20

More Related