1 / 8

Orbit Orbit condition Example Whiteboards

Orbit Orbit condition Example Whiteboards. Orbit. m s v 2 r or m s 4  2 r T 2. m s. =. Gm s m c r 2. m c. Example 1 - What is the velocity of orbit 250 miles above the earth? r = 6.38x10 6 m + (250 mi)(1609 m/mi) = 6782250 m

siobhan-crofton
Télécharger la présentation

Orbit Orbit condition Example Whiteboards

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Orbit • Orbit condition • Example • Whiteboards

  2. Orbit msv2 r or ms42r T2 ms = Gmsmc r2 mc Example 1 - What is the velocity of orbit 250 miles above the earth? r = 6.38x106 m + (250 mi)(1609 m/mi) = 6782250 m mc = 5.98 x 1024 kg, use mv2/r = Gmm/r2 Do algebra first!!!!!!!! TOC

  3. Orbit msv2 r or ms42r T2 ms = Gmsmc r2 mc Example 2 - What is the radius of a geosynchronous orbit? T = 23:56:04 = 23(3600) + 56(60) + 4 = 86164 s mc = 5.97 x 1024 kg, use m42r/T2 = Gmm/r2 TOC

  4. Whiteboards: Orbit 1 | 2 | 3 | 4 TOC

  5. msv2 r • = Gmsmc • r2  v = • Gmc • r What is the velocity of orbit 7.2 x 106 m from the earth’s center for a 23.5 kg object? Me = 5.97 x 1024 kg 7437 m/s W 7400 m/s

  6. msv2 r • = Gmsmc • r2 At what distance from the moon’s center is the orbital velocity 52.5 m/s? Mm = 7.36 x 1022 kg • r = Gmc • v2 1781086621 m W 1.78 x 109 m

  7. ms42r T2 • = Gmsmc • r2 You are orbiting 2.3 km from the center of an asteroid in a 24,600 kg spacecraft with a period of 2500 seconds. What must be the mass of the asteroid? mc = 42r3 GT2 1.15223E+15 kg W 1.2 x 1015 kg

  8. ms42r T2 • = Gmsmc • r2  42r3 Gmc T = You are orbiting 8.5 x 106 m from the center of a planet with a mass of 4.5 x 1024 kg. Your spaceship has a mass of 45,120 kg. What is your period of motion? 8987.5 s W 9.0 x 103 s

More Related