1 / 18

Energy

Energy. A Give and Take. 10.1 The Nature of Energy. Energy: the ability to do work or produce heat Potential energy (store energy): energy due to position or composition. Kinetic energy (motion energy): energy due to motion of the object and depends on the mass of the object and its velocity

sollars
Télécharger la présentation

Energy

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Energy A Give and Take

  2. 10.1 The Nature of Energy • Energy: the ability to do work or produce heat • Potential energy (store energy): energy due to position or composition

  3. Kinetic energy (motion energy): energy due to motion of the object and depends on the mass of the object and its velocity • KE = ½ (mv2) • Law of conservation of energy: that energy can be converted from one from to another but can be neither created or destroyed. • Energy of the universe is constant

  4. The nature of energy • Work: force acting over a distance • w = F x d • State function: property of the system that changes independently of its pathway

  5. Temperature and Heat • Temperature: is a measure of the random motions of the components of a substance • E.g H2O molecules move rapidly in hot water than in cold water • Heat: a flow of energy due to a temperature difference • Tfinal = average temp from mixing (hot & cold temp)

  6. Exothermic and Endothermic Process • System – everything we focus on in experiment • Surroundings– everything other the system • exothermic (energy flows out of system to surrounding (via heat) • endothermic ( energy flows into system from surrounding (via heat)

  7. Examples • Identify whether these process are exothermic or endothermic • Your hand gets cold when you touch ice • The ice melts when you touch it • Propane is burning in a propane torch • Two chemicals mixing in a beaker give off heat

  8. Thermodynamics • Is the study of energy. • First law of thermodynamics: the energy of the universe is constant • Internal energy – energy of the system • ∆E = q + w • ∆ => change in the function • q => represents heat • w => represents work

  9. 10.5 Measuring Energy changes • calorie: the amount of energy (heat) required to raise the temperature of one gram of water by 1oC • 1Calorie = 1000 calories • Joule (J) – SI unit • 1 calories = 4.184 joules

  10. Converting Calories to Joules • Express 60.1 cal of energy in units of Joules • How many calories of energy corresponds to 28.4 J?

  11. Calculating Internal Energy • Calculate ΔE for q = 34 J, w = -22 J • ΔE = q + w • ΔE = 34 J + (-22 J) = 12 J Is this exothermic or endothermic? ΔE > 0, therefore it is endothermic

  12. Specific heat • The amount of energy required to change the temperature of one gram of a substance by 1oC • Denoted as s • Heat required = specific heat x mass x change in temp • Q = s x m x ∆T

  13. Calculating Energy Requirements • Determine the amount of energy (heat) in joules required to raise the temperature of 7.40 g water from 29.0oC to 46.0 oC Energy required or Q = s x m x ΔT swater = 4.184 J/goC Q = 4.184 J x 7.40 g x 17°C g °C = 526 J

  14. A 5.63 g sample of solid gold is heated from 21oC to 32oC. How much energy in Joules and calories is required? • Q= s x m x ΔT sgold = 0.13 J/g oC Q= 0.13 J x 5.63 g x 11°C g °C = 8.1 J

  15. A 55.0 g aluminum block initially at 27.5°C absorbs 725 J of heat. What is the final temperature? • Q= s x m x ΔT • ΔT= Tfinal – Tinitial saluminum = 0.89 J/g oC 725 J = 0.89 J x 55.0 gx Tf -27.5°C g°C 725 J = Tf – 27.5 °C 48.95J/°C

  16. 725 J = Tf – 27.5 °C 48.95J/°C 14.8 °C = Tf – 27.5 °C Tf = 42.3 °C

  17. A sample of gold requires 3.1 J of energy to change its temperature from 19oC to 27oC. What is the mass of this sample of gold? Q = s x m x ΔT sgold = 0.13 J/g oC

  18. 3.1 J = 0.13 J x m x 8 °C g °C 3.1 J= m 8 °C x 0.13 J/g°C m = 2.98 g or 3.0 g

More Related