50 likes | 137 Vues
Problem 36 Chapter 3. a) Two will have disease?. b) None with Disease?. FACT(3)/(FACT(3)*FACT(0))*(Prob^0)* (1-Prob)^3 = 0.63. c) At least 1not diseased nor carrier. d) First diseased third?. (Prob^2)*(1-Prob)^1 = 0.05.
E N D
b) None with Disease? FACT(3)/(FACT(3)*FACT(0))*(Prob^0)* (1-Prob)^3 = 0.63
d) First diseased third? (Prob^2)*(1-Prob)^1 = 0.05