1 / 5

Chemical Equilibrium Calculation for the Reaction of PCl3 and Cl2 to Form PCl5

This document explores the equilibrium calculation for the chemical reaction between phosphorus trichloride (PCl3) and chlorine gas (Cl2) to produce phosphorus pentachloride (PCl5). Using the equilibrium constant (K = 0.0870), we derive expressions for the concentrations of the reactants and products at equilibrium. We discuss the changes in molar concentrations and solve for the values of X representing changes in concentration due to the shift in equilibrium. The final equilibrium concentrations for PCl3, Cl2, and PCl5 are calculated in terms of their atm values.

talon-delaney
Télécharger la présentation

Chemical Equilibrium Calculation for the Reaction of PCl3 and Cl2 to Form PCl5

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Q = PPCL5 = 0.10 = 0.5 PPCL3 * PCl2 0.30 * 0.60Q (0.58) > K (0.0870) therefore reverse PCl3(g) + Cl2(g) PCl5(g)

  2. K = PPCL5 = (0.10-X) PPCL3 * PCl2 (0.30+X) (0.60+X)PCl3(g) + Cl2(g) PCl5(g)

  3. 0.0870= (0.10-X) (0.30+X) (0.60+X) (0.10-X) (0.18 + 0.90X + X2)

  4. 0.0870X2 + 0.0783X + 0.0157 = 0.10-X 0.0870X2 + 1.0783X - 0.0843 = 0 X= -1.0783 + (1.0783)2 -4(0.0870)(-0.0843) 2(0.0870)

  5. X= -1.0783 + (1.0783)2 -4(0.0870)(-0.0843) 2(0.0870)X= -1.0783 + 1.0918 = 0.078 0.174PCL3 = 0.30 + 0.078 = 0.378 atmCl2 = 0.60 + 0.078 = 0.678 atmPCl3 = 0.10 – 0.078 = 0.022 atm

More Related