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This document covers the methodology for determining flow rates and head losses in a dam system using flow nets. A specific example is provided wherein flow per unit width is calculated, accompanied by the total head loss measurement. The calculations detail the number of flow channels and head drops, allowing for comprehensive insights into the performance of the dam structure. Finally, the analysis offers flow rates over the dam's length, showing an efficient estimation of water flow capacity and highlights essential hydraulic principles.
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EXAMPLE 1 SECTION 1 SECTION 2 TOTAL k = 4 ft/hour = 6,67x10-2 ft/min
EXAMPLE 2 Determination of h Section 1 Section 2 h = 38.33 cm
Flow Nets: an example The flow net is drawn with: m = 5 n = 17
Flow Nets: the solution • Solve for the flow per unit width: q = (m/n) K h = (5/17)(150)(35) = 1544 ft3/day per ft
From the flow net, the total head loss, H, is 6.2 -2.2 = 4.0 meters. • There are 6 flow channels (m) and 21 head drops along each flow path (n): • Q = (KmH/n) x dam length = (0.527 m/day x 6 x 4m / 21) x (dam length) = 0.60 m3/day per m of dam • = 43.4 m3/day for the entire 72-meter length of the dam