1 / 16

Optimal Oblivious Routing in Polynomial Time

Optimal Oblivious Routing in Polynomial Time. Yossi Azar Amos Fiat Haim Kaplan Tel-Aviv University. Harald Räcke Paderborn. Edith Cohen AT&T Labs-Research. Routing, Demands, Flow, Congestion. Routing: a unit s-t flow for each origin-destination pair:

tangia
Télécharger la présentation

Optimal Oblivious Routing in Polynomial Time

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Optimal Oblivious Routing in Polynomial Time Yossi Azar Amos Fiat Haim Kaplan Tel-Aviv University Harald Räcke Paderborn Edith Cohen AT&T Labs-Research STOC 2003

  2. Routing, Demands, Flow, Congestion • Routing: a unit s-t flow for each origin-destination pair: fab(i,j)>=0 routing for OD pair a,b on edge (i,j) • Demands:Dab >= 0 for each OD pair a,b • Flow on edge e=(i,j) when routing D with f: • flow(e,f,D)=Sab fab(i,j)Dab • Congestion on edge e=(i,j) when routing D with f: cong(e,f,D)=flow(e,f,d)/capacity(e) STOC 2003

  3. Congestion, Oblivious Routing • Congestion of demands D with routing f: cong(f,D)= maxe cong(e,f,D) • Optimal routing for D: min possible congestion: opt(D) = minf cong(f,D) • Oblivious ratio of f: obliv(f)= maxD cong(f,D)/opt(D) • Optimal Oblivious Ratio of G: obliv-opt(G)=minf obliv(f) STOC 2003

  4. Example 2 1 3 4 Routing f: Route each OD pair on direct edge Demands D: unit demand for all pairs cong(e,f,D)=2 for all edges Thus, cong(f,D)=2 (f is optimal for D) STOC 2003

  5. 2 1 3 4 Example Routing f: Route each OD pair on direct edge Demands D: unit demand for ONE pair cong(e,f,D)=1 for used edge, 0 otherwise. Thus, cong(f,D)=1 (f is NOT optimal for D) STOC 2003

  6. Example 2 1 3 4 Routing f: Route each OD pair on the 3 1,2 hop paths Demands D: unit demand for one pair cong(e,f,D)=1/3 for used edges cong(f,D)=1/3 “direct” routing has oblivious ratio >= 3 STOC 2003

  7. Example 2 1 3 4 Routing f: Route each OD pair on the 3 1,2 hop paths Demands D: unit demand for all pairs cong(e,f,D)=10/3 for all edges (10 pairs use each edge) cong(f,D)=10/3 (f is NOT optimal for D) 2-hop routing has oblivious ratio >= 5/3 STOC 2003

  8. Optimal oblivious routing • Balances performance across all demand matrices. • Why is it interesting? • Demands are dynamic • Changes to routing are hard • Sometimes we don’t know the demands STOC 2003

  9. History • Specific networks, VC routing • Raghavan/Thompson 87…Aspnes et al 93 • Valiant/Brebner 81: Hypercubes • Räcke 02: Any undirected network has an oblivious routing with ratio O(log^3 n)!! • Questions: • Poly time algorithm. • Get an optimal routing. • Directed networks? STOC 2003

  10. LP for Optimal Oblivious Ratio • Minimize r s.t. fab(i,j) is a routing (1-flow for every a,b) For all demands Dab >= 0 which can be routed with congestion 1: For all edges e=(i,j) : (cong(e,f,D) <= r) Sab fab(i,j)Dab/capacity(e) <= r But… Infinite number of constraints  use Ellipsoid STOC 2003

  11. Separation Oracle • Given a routing fab(i,j), find its oblivious ratio and a demand matrix D which maximizes the ratio (the “worst” demands for f). For each edge e=(i,j) solve the LP (and then take the maximum over these LPs): • Maximize Sab fab(i,j)Dab/capacity(e) • gab(i,j) is a flow of demand Dab >= 0 • For all edges h,Sgab(h) <= capacity(h) ** Need to insure that the numbers don’t grow too much STOC 2003

  12. Directed Networks (Asymmetric link capacities) • Our algorithm computes optimal oblivious routing for undirected and directed networks. • Räcke’s O(log^3 n) bound applies only to undirected networks. • We show that some directed networks have optimal oblivious ratio of W(sqrt(n)). STOC 2003

  13. {i,j} ( ) k 2 k/2 i j k Any flow from {i,j} to t is split on the two possible paths. Thus, a routing is determined by the split ratio for each {i,j}. t For any routing f, there is at least one mid-layer node i that routes >= half the flow for >= k/2 pairs. “Bad” demands for f: 1 on pairs {i,*} to t, 0 otherwise. congestion is >= k/4 with f. But optimal is 1 (via alternate paths) STOC 2003

  14. Extensions • Subset of OD pair demands • Ranges of demands • Node congestion • Limiting dilation STOC 2003

  15. Follow up/subsequent work • Polytime construction of a Räcke-like decomposition (two SPAA 03 papers: Harrelson/Hildrum/Rao Bienkowski/Korzeniowski/Räcke) • More efficient polynomial time algorithm (Applegate/Cohen SIGCOMM 03) • Oblivious routing on ISP topologies (Applegate/Cohen SIGCOMM 03) • Online oblivious routing (Bansal/Blum/Chawla/Meyerson SPAA 03) STOC 2003

  16. Open Problems • Tighten Räcke’s bound O(log^3 n)  W(log n) (Currently, O(log^2 n log log n) by Harrelson/Hildrum/Rao 03) • Single source demands: Is there a constant optimal oblivious ratio ? STOC 2003

More Related