SlideServe
Télécharger Obtenir Pro
Menu
Accueil Pro
Préférences
ApparenceLight Aide et commentaires
© SlideServe · v2026

Warm Up Construct each of the following. 1. A perpendicular bisector. 2. An angle bisector.

tangia avatar
tangia
8 diapositives · 371 Views · Oct 13, 2014

Warm Up Construct each of the following. 1. A perpendicular bisector. 2. An angle bisector. 3. Find the midpoint and slope of the segment (2, 8) and (–4, 6). When a point is the same distance from two or more objects, the point is said to be equidistant from

#warm up construct each of the following. 1. a perpendicular bisector. 2. an angle bisector. #warm up construct each of the following. 1. a perpendicular bisector. 2. an angle bisector. ppt #powerpoint #presentation
Warm Up Construct each of the following. 1. A perpendicular bisector. 2. An angle bisector. - slide 1
01 / 8Warm Up Construct each of the following. 1. A perpendicular bisector. 2. An angle bisector.
1 / 17

Télécharger la présentation

Warm Up Construct each of the following. 1. A perpendicular bisector. 2. An angle bisector.
Une image / un lien ci-dessous est fourni (tel quel) pour télécharger la présentation

Politique de téléchargement : le contenu du site vous est fourni TEL QUEL pour votre information et votre usage personnel ; il ne peut être vendu, concédé sous licence ni partagé sur d’autres sites sans l’accord de son auteur.Le contenu vous est fourni TEL QUEL, pour votre information et votre usage personnel uniquement. Téléchargez la présentation en cliquant sur ce lien. Lors du téléchargement, si vous ne parvenez pas à télécharger une présentation, l’éditeur a peut-être supprimé le fichier de son serveur.Pendant le téléchargement, si vous ne parvenez pas à obtenir une présentation, le fichier a peut-être été supprimé par l’éditeur.

F I N

Plus de contenu associé

Transcription de la présentation

  1. Warm Up Construct each of the following. 1.A perpendicular bisector. 2. An angle bisector. 3. Find the midpoint and slope of the segment (2, 8) and (–4, 6).

  2. When a point is the same distance from two or more objects, the point is said to be equidistantfrom the objects. Triangle congruence theorems can be used to prove theorems about equidistant points.

  3. A locus is a set of points that satisfies a given condition. The perpendicular bisector of a segment can be defined as the locus of points in a plane that are equidistant from the endpoints of the segment. Remember that the distance between a point and a line is the length of the perpendicular segment from the point to the line. Example 1A: Find each measure. MN MN = LN  Bisector Thm. MN = 2.6 Substitute 2.6 for LN.

  4. Example 1B: Find each measure. TU TU = UV  Bisector Thm. 3x + 9 = 7x – 17 Substitute the given values. 9 = 4x – 17 Subtract 3x from both sides. 26 = 4x Add 17 to both sides. 6.5 = x Divide both sides by 4. So TU = 3(6.5) + 9 = 28.5.

  5. Based on these theorems, an angle bisector can be defined as the locus of all points in the interior of the angle that are equidistant from the sides of the angle.

  6. Example 2A: Find the measure. BC BC = DC  Bisector Thm. BC = 7.2 Substitute 7.2 for DC. Example 2B: Find mMKL. Since, JM = LM, KJ  JM and KL  LM, KM bisects JKL by the Converse of the Angle Bisector Theorem. mMKL = mJKM Def. of  bisector 3a + 20 = 2a + 26 Substitute the given values. a + 20 = 26 Subtract 2a from both sides. a= 6 Subtract 20 from both sides. So mMKL = [2(6) + 26]° = 38°

  7. Example 4: Write an equation in point-slope form for the perpendicular bisector of the segment with endpoints C(6, –5) and D(10, 1). Step 1 Find the midpoint of . The perpendicular bisector of is perpendicular to at its midpoint. mdpt. of = Midpoint formula. Step 2 Find the slope of the perpendicular bisector. Slope formula.

  8. Step 3 Use point-slope form to write an equation. The perpendicular bisector of has slope and passes through (8, –2). Since the slopes of perpendicular lines are opposite reciprocals, the slope of the perpendicular bisector is Substitute –2 for y1, for m, and 8 for x1. y – y1 = m(x – x1) Point-slope form