Chapter 3 Genetic analysis of l inkage and chromosome mapping. Key points: 1. Sex-chromosome and sex determination 2. Linkage versus independent assortment 3. Incomplete linkage 4. Mapping in Drosophila and maize 5. The accuracy of mapping experiments
01 / 66Chapter 3 Genetic analysis of l inkage and chromosome mapping
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Chapter 3 Genetic analysis of l inkage and chromosome mapping
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Chapter 3Genetic analysis of linkage and chromosome mapping • Key points: • 1. Sex-chromosome and sex determination • 2. Linkage versus independent assortment • 3. Incomplete linkage • 4. Mapping in Drosophila and maize • 5. The accuracy of mapping experiments • 6.The genetic map of drosophila • 7.Somatic cell hybridization and human gene mapping
Section 1 Sex-chromosome and sex determination • 1. The discovery of sex-chromosomes • 2. types of sex determination. Basically, four type of chromosomal sex-determining mechanisms exist; the XY, ZW, X0, and compound chromosomal mechanism: • (1) The XY system: male(XY), female(XX). Including humans, mammals, some amphibians and fish, as well as many insects and dioecious plants, etc. • (2) The ZW system: male(ZZ), female(ZW). Including birds, Lepidoptera, some amphibians, reptiles, and Silkworm • (3) XO system: male(XO), female(XX). Including Orthoptera insects such as grasshoppers and cockroach • Some animals such as Bniella, their sexes are determined by environment factors
Sex-linked inheritance • When homozygous dominant genes are passed with homogametic-sex individuals, dominant characters are expressed in both male and female individuals in the F1 generation. In the F2 generation, the separation proportion of dominance versus recessiveness is 3:1 and that of sex 1:1. The meternal grandfather passes the character to his grandson • 2. When homogametic-sex individuals pass homozygous recessive genes to their offspring, the criss-cross inheritance exihited in the F1 generation; that is, the mother passes traits to her son and the father to his daughter. In the F2 generation, the separation ratio of traits and sexes is 1:1 • 3. The transmission and expression of genes located on sexual chromosomes are dependent on sexes. Results of reciprocal crosses show differences in phenotypic ratios in both F1 and F2 generations
Section 4 Y chromosome and sex determination in Drosophila The critical factor in determining sex is the ratio of X chromosomes to the number of haploid sets of autosomes (A) present: 1. when X \ A = 0.5, the male 2. when X \ A = 1, the female 3. when the ratio of X \ A ranges 0.5 from 1, the intersexual
Section 5 Dosage compensation effect 1. Barr bodyrefers to an inactivated X chromosome, which is also called sex chromatin body 2.Dosage compensation effect: If one of the two X chromosomes is inactive in the cells of females, the dosage of genetic information that can be expressed in males and females is equivalent 3. Lyon hypothesis 4. Molecular mechanism of random X inactivation
The relationships between the three genetic laws The law of separation is the basis of the independent assortment law and the law of linkage and crossing over, which lead to a wide variety of genetic variations in the organisms For the independent assortment law and the law of linkage and crossing over, there existed the difference in the transmission of genetic recombination. The genetic recombinations in the former result from the different chromosomes and that in the latter from the homologue Their genetic variations are limited by the length and number of chromosomes, respectively
Linkage inheritance Linkage inheritance: is the tendency of genes located in the same chromosome to be associated in inheritance. Linked genes have their loci along the same chromosome, do not assort independently, but can be separated by crossing over. Complete linkage produces only parental or non-crossover gametes. Incomplete linkage produces this exchanged gamete, called recombinant or crossover gametes
Purple and long (PPLL)×red and round (ppll) • Results: • Phenotypes of F1 are dominant,four phenotypes of F2; • The ratio of four phenotype of F2is different of classic ratio of 9:3:3:1,two parental phenotypes are higher than theory number,and two combined phenotypes are less than theory number
Purple and round (PPll)×red and long (ppLL) • Results: • Phenotypes of F1 are dominant,four phenotypes of F2; • The ratio of four phenotype of F2is different of classic ratio of 9:3:3:1,two parental phenotypes are higher than theory number,and two combined phenotypes are less than theory number
Coupling phase and repulsion phase Coupling phase: Allelic arrangement in which mutant are on the same chromosome and wild-type alleles are on the homologue Repulsion phase: allelic arrangement in which each homologous chromosome has mutant and wild-type alleles coupling phase versus repulsion phase 相引相:两个显性性状(基因)或两个隐性性状(基因)连在一起遗传 相斥相:一个显性性状(基因)和一个隐性性状(基因)连在一起遗传
Crossing-over Value(交换值) Cross-over value,called recombined ratio,refer to the percent of recombined gametes. The formula is: 亲本型配子+重组型配子 What are method used to test the number of recombined gametes? Test cross and self-crossing
Cross over value between P-L(1) • Given the ratio of four gamete produced by F1 PL, Pl*, pL*, and pl is a, b, c, and d respectively; Then: • a+b+c+d=1 • a=d, b=c
Cross over value between P-L(2) • Four phenotypes of nine genotype of F2 are: • P_L_ (PPLL, PPLl, PpLL, PpLl): a2+2ab+2ac+2bc+2ad • P_ll (PPll, Ppll) : b2+2bd • ppL_ (ppLL, ppLl) : c2+2cd • ppll : d2 The recessive homogenous individuals (ppll) number of F2 may gains from observation (1338),its ratio is (1338/6952)
Gene location/localization/mapping基因定位与染色体作图 • Gene location/localization:refer to determine location and sequence of genes on chromosome. • Related distance of linked genes may be determined on the basis of cross-over value between two gene, and the sequence may not. • For example: • Maize color C/colorless c, and round Sh/wrinkled sh are on chromosome 9;and the cross-over value between C-Sh is 3.6%. • Hence, there are three or more than three pairs of gene involved in gene locating Linkage groups is a group of gene that have their loci on the same chromosome. In a species, there are as many linkage groups as there are homologous pairs of chromosome or as the haploid number of chromosomes
Sequence of two pair of genes The cross-over value between C-Sh is 3.6 units; Then, there are two possible sequences of them
Two-point test (1)两点测验 • Three crosses between three pairs of gene • For example: there are three pairs of linked genes on chromosome 9. • Grain color: color (C) dominant versus colorless c recessive; • shape:round Sh dominant versus wrinkled sh recessive; • Starch:non-sticky Wx dominant versus sticky wx recessive. • (1) (CCShSh×ccshsh) F1 × ccshsh • (2) (wxwxShSh×WxWxshsh) F1 × wxwxshsh • (3) (WxWxCC×wxwxcc) F1 × wxwxcc
Two points test (3) Determine distance and related location of between genes. C-Sh: 3.6 Wx-Sh: 20 Wx-C: 22
Three points test (1/7-2/7) 1. Cross: P: wrinkled, non-sticky, color × round, sticky, colorless shsh ++ ++ ++ wxwx cc ↓ F1and test cross: round, non-sticky, color × wrinkled, sticky, colorless +sh +wx +c shsh wxwx cc ↓ 2. Observe traits and class How many phenotypes of F2 , if incomplete linkage?
Three points test(5/7) 5. Determine the related location Compare parental gametes with two-cross over gametes:The different allele located between two same genes For example:to compare + wx c and sh wx c show only sh is distinct,hence, sh locate between wx and c; Likewise,comparsion sh + + and + + + show that only sh locus is distinct,this also suggest sh locate between wx and c