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1’s and 2’s complement

1’s and 2’s complement. One’s Complement (4-bit binary). ( + )  ditulis seperti biasa ( - )  “1” diubah menjadi “0” dan “0” diubah menjadi “1”. Two’s Complement (4-bit binary). ( + )  ditulis seperti biasa ( - )  “1” diubah menjadi “0” dan “0” diubah menjadi “1”

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1’s and 2’s complement

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  1. 1’s and 2’s complement

  2. One’s Complement (4-bit binary) ( + )  ditulissepertibiasa ( - )  “1” diubahmenjadi “0” dan “0” diubahmenjadi “1”

  3. Two’s Complement (4-bit binary) ( + )  ditulissepertibiasa ( - )  “1” diubahmenjadi “0” dan “0” diubahmenjadi “1” Tambahkan “1”

  4. Contoh 2’s Complement Desimal = (+5) Binary = 0101 Desimal = (-5) Binary : Ubahke binary biasa = 0101 Ganti “0” menjadi “1” dan “1” menjadi “0” = 1010 Tambahkandengan “1” = 1011

  5. Penjumlahanpada binary • 0 + 0 = 0 • 0 + 1 = 1 • 1 + 0 = 1 • 1 + 1 = 0, and carry 1 to the next more significant bit

  6. Contohpenjumlahan binary 1 1 0  0  0  1  1  0  1  0   =   26 + 0  0  0  0  1  1  0  0   =   12 0  0  1  0  0  1  1  0   =   38

  7. Penguranganpada binary • 0 - 0 = 0 • 0 - 1 = 1, and borrow 1 from the next more significant bit • 1 - 0 = 1 • 1 - 1 = 0

  8. Contohpengurangan binary

  9. Penjumlahanpada 1’s complement 6 + 3 = …. 6 - 3 = …. 6 - 3 ---- 3 6 3 == 9 0110 - 0011 0011

  10. Penguranganpada 1’s complement 1 2 3 overflow 4 5

  11. Penguranganpada 1’s complement

  12. Penjumlahanpada2’s complement 5 +2 = … 0101 5 + 0010 2 0111 7 5 + (-2) = … 0101 5 + 1110 -2 10011 3

  13. Penguranganpada 2’s complement

  14. Penguranganpada 2’s complement Overflow : Discard!!!

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