1 / 15

STOICHIOMETRY

STOICHIOMETRY. 436. 5.6 – To determine, using stoichiometric calculations, the quantity of a substance involved in a chemical reaction. 5.8 – To solve numerical problems related to stoichiometry. Recall:.

villafane
Télécharger la présentation

STOICHIOMETRY

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. STOICHIOMETRY 436 • 5.6 – To determine, using stoichiometric calculations, the quantity of a substance involved in a chemical reaction. • 5.8 – To solve numerical problems related to stoichiometry.

  2. Recall: A mole is the amount of substance that contains 6.02 x 1023 particles of that substance n (moles) = mass of substance (g) molar mass of substance (g/mol)

  3. Stoichiometry: • Stoichiometry: • uses ratios of a chemical reaction to determine the amounts of elements/ compounds (reactants & products) involved in a chemical change

  4. Ex. 2Mg + O2 2MgO Magnesium metal reacts with oxygen to produce magnesium oxide. • Mole Ratio – • describes the ratio in which the substances combine • Ex. for every 2 Mg, 1 O2 needed • used to predict what will happen • Ex. for every 2 Mg & 1 O2, 2 MgO will be produced 2 : 1 : 2

  5. Ex #1 2Mg + O2 2MgO 4 moles of magnesium metal reacts with oxygen to produce magnesium oxide. How many moles of MgO are produced? First 2 : 1 : 2 Mole Ratio Second from mole ratio Set up ratio 2 moles Mg 2 moles MgO = 4 moles Mg ? moles MgO from question

  6. Ex #1 cont... Third Solve by cross multiplying 2 moles Mg 2 moles MgO = 4 moles Mg ? moles MgO 4 x 2 ÷ 2 4 moles MgO are produced

  7. Ex #2 4Fe + 3O2 2Fe2O3 Iron metal reacts with oxygen to produce 3 moles of iron (III) oxide. How many moles of oxygen were needed in the reaction? First 4 : 3 : 2 Mole Ratio Second from mole ratio Set up ratio 3 moles O2 2 moles Fe2O3 = ? moles O2 3 moles Fe2O3 from question

  8. Ex #2 cont... Third Solve by cross multiplying 3 moles O2 2 moles Fe2O3 = ? moles O2 3 moles Fe2O3 3 x 3 ÷ 2 4.5 moles O2are needed

  9. Ex #3 N2 + 3H2 2NH3 How many moles of nitrogen gas & hydrogen gas are required to make 7.5 mol of ammonia? 1 : 3 : 2 Solve for moles of N2: 11.25 moles H2are required 1 mole N2 2 moles NH3 = ? moles N2 7.5 moles NH3 Solve for moles of H2: 3.75 moles N2are required 3 mole H2 2 moles NH3 = ? moles H2 7.5 moles NH3

  10. n (moles) = mass of substance (g) molar mass of substance (g/mol) We can now add mass into problems involving stoichiometry. Recall, Ex. How many moles are in 12.5g of Ca? n (moles) = 12.5g 40g/mol 0.3125 mol of Ca Ex. How many moles are in 2.4g of NO2? n (moles) = 2.4g 46g/mol 0.052 mol of NO2

  11. Ex #4 2Li + F2 2LiF How many moles of Li are needed to react with fluorine gas to make 435g of lithium fluoride? 2 : 1 : 2 First Solve for moles of LiF: Second: n (moles) = 435g 26g/mol Solve for moles of Li: 16.73 mol of LiF 2 moles Li 2 moles LiF = ? moles Li 16.73 mol LiF 16.73 moles Liare needed

  12. How many grams of NaClO3 must be decomposed to produce sodium chloride & 1.65 moles of oxygen? Ex #5 2NaClO3 2NaCl + 3O2 2 : 2 : 3 First Solve for moles of NaClO3: 2 mol NaClO3 3 mol O2 = ? mol NaClO3 1.65 mol O2 1.1 mol of NaClO3 Second Solve for mass of NaClO3: 116.6g of NaClO3 1.1 mol = ? g 106 g/mol

  13. 3g of magnesium react with how many grams of hydrochloric acid to produce hydrogen gas & magnesium chloride? Ex #6 Mg + 2HCl  MgCl2 + H2 1 : 2 : 1 : 1 First Solve for moles of Mg: Third n = 3 g 24 g/mol Solve for mass of HCl: 0.25mol = ? g 36 g/mol 0.125 mol of Mg Second 9g of HCl Solve for moles of HCl: 1 mol Mg 2 mol HCl = 0.25 mol of HCl 0.125 mol Mg ?mol HCl

  14. Key Points: • Always find moles first!!! • Use mole ratio to find the moles of each reactant & product • Remember, the equation must be balanced to give you the mole ratio n (moles) = mass of substance (g) molar mass of substance (g/mol)

  15. Practice: • Worksheet #

More Related