1 / 22

Assignment: Read Chapter 20 Exercises p265: 1, 2, 3a,b

Mar. 29 Statistic for the day: 80.4% of Penn State students drink; 55.2% engage in “high-risk drinking” source: Pulse Survey, n = 1446, margin of error = 2.6%. Assignment: Read Chapter 20 Exercises p265: 1, 2, 3a,b. Sample means: measurement variables.

wyatt-macias
Télécharger la présentation

Assignment: Read Chapter 20 Exercises p265: 1, 2, 3a,b

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Mar. 29 Statistic for the day: 80.4% of Penn State students drink; 55.2% engage in “high-risk drinking”source: Pulse Survey, n = 1446, margin of error = 2.6% Assignment: Read Chapter 20 Exercises p265: 1, 2, 3a,b

  2. Sample means: measurement variables Suppose we want to estimate the mean weight at PSU Data from stat100.2 survey. Sample size 237. Mean value is 152.5 pounds. Standard deviation is about (240 – 100)/4 = 35

  3. What is the uncertainty in the mean? Suppose we take another sample of 237. What will the mean be? Will it be 152.5 again? Probably not. Consider what happens if we take 1000 samples each of size 237 and compute 1000 means.

  4. Standard deviation is about (157 – 148)/4 = 9/4 = 2.25

  5. Note: When we have measurement data and we consider • the sample mean, there are two different standard deviations: • The original standard deviation of the data. We estimated • that from the original histogram of the data. • The standard deviation of the sample mean. We estimated • that from a histogram of 1000 sample means. In general we will have to be given the standard deviation of the data. Or we will have to estimate it from a histogram. But once we have the standard deviation of the data (called the sample standard deviation) we can skip the histogram of sample means and use a formula.

  6. Formula for estimating the standard deviation of the sample mean (don’t need histogram) Suppose we have the standard deviation of the original sample. Then the standard deviation of the sample mean is: Jargon: The standard deviation of the mean is also called the standard error or the standard error of the mean and abbreviated SEM or SE Mean.

  7. So in our example of weights: The standard deviation of the sample is about 35. Write SD = 35. Sample size is 237 Hence by our formula: SEM = SD/square root of sample size Standard error of the mean is 35 divided by the square root of 237: SEM = 35/15.4 = 2.3 So the margin of error of the sample mean is 2x2.3 = 4.6 Report 152.5 + 4.6 or 147.9 to 157.1

  8. Using the margin of error as 2 SEMs we really have a 95% confidence interval for the pop mean.

  9. sample mean: 152.5 (given) • sample standard deviation: SD = 35 (given) • sample size: 237 (given) • standard error of the mean: SEM = 35/sqrt(237) = 2.3 • (you calculate) • 5. number of SEMs for 95% confidence coefficient: 2 • (you look up in a normal z table) • Now you put it all together: • 6. 95% confidence interval for pop mean: 152.5 + 2x(2.3) • 152.5 + 4.6 • 147.9 to 157.1 The steps for 95% confidence interval:

  10. Example: Estimate the true population mean amount • spent by stat 100 students for text books in fall 2001. • Include a 98% confidence interval. • From the class sample survey • mean: 275 dollars • sample standard deviation: SD = 120 dollars • sample size: 100 • standard error of the mean: • SEM = SD/sqrt(100) = 120/10 = 12 • number of SEMs for 98% confidence interval: 2.33 • 6. 98% confidence interval: 275 + 2.33x(12) • 275 + 27.96 • 247.04 to 302.96

  11. Interpretation: We estimate that the population of stat100 students spent about $275. 98% confidence interval is $247 to $303, a reasonable set of values for the pop mean. So we believe that the true pop mean amount spent on books this semester is between $247 and $303 with our best guess of $275.

  12. Fibonacci Guess the next number in the sequence 1, 1, 2, 3, 5, 8, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, … Called a Fibonacci sequence. Ratios of pairs after a while equal approximately .618 eg. 8/13 = .615 13/21 = .619 21/34 = .618 34/55 = .618

  13. width length If Then the rectangle is called the golden rectangle.

  14. Daisy Head 21 clockwise spirals 34 counterclockwise

  15. Parthenon in Athens

  16. Villa in Paris by Le Corbusier

  17. St. Jerome Leonardo da Vinci

  18. La Parade Georges Seurat Place de la Concorde Piet Mondrian

  19. The golden rectangle has become an aesthetic standard for western civilization. It appears in many places: architecture art pyramids business cards credit cards Research question: Do non-western cultures also incorporate the golden rectangle as an aesthetic standard?

  20. Width to Length ratios for rectangles appearing on beaded baskets of the Shoshoni 0.693 0.662 0.690 0.606 0.570 0.749 0.652 0.628 0.609 0.844 0.654 0.615 0.668 0.601 0.576 0.670 0.606 0.611 0.553 0.633 0.625 0.610 0.600 0.633 0.595

  21. Question: Is the golden rectangle (.618) a reasonable • value for the mean of the population of Shoshoni • rectangles? • sample mean: .638 • sample standard deviation: SD = .061 • sample size: 25 • standard error of the mean: SEM = .012 • (I calculated if for you.) • Could you create a 95% confidence interval for the population mean? (We’d like to know whether .618 is in this interval.)

More Related