Download Presentation
## TMAT 103

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -

**TMAT 103**Chapter 7 Quadratic Equations**TMAT 103**§7.1 Solving Quadratic Equations by Factoring**§7.1 – Solving Quadratic Equations by Factoring**• Quadratic Equation – general form: • Key principle – Zero Factor Property: • If ab = 0, then either a = 0, b = 0, or both**§7.1 – Solving Quadratic Equations by Factoring**• Solving a Quadratic Equation by Factoring (b 0) • If necessary, write the equation in the form ax2 + bx + c = 0 • Factor the nonzero side of the equation • Using the preceding problem, set each factor that contains a variable equal to zero • Solve each resulting linear equation • Check**§7.1 – Solving Quadratic Equations by Factoring**• Examples – Solve the following by factoring x2 – 6x + 8 = 0 2x2 + 9x = 5 x – 2x2 = 0**§7.1 – Solving Quadratic Equations by Factoring**• Solving a Quadratic Equation by Factoring (b = 0) • If necessary, write the equation in the form ax2 = c • Divide each side by a • Take the square root of each side • Simplify the result, if possible**§7.1 – Solving Quadratic Equations by Factoring**• Examples – Solve the following by factoring 4x2 = 9 16 – x2 = 0**TMAT 103**§7.2 Solving Quadratic Equations by Completing the Square**§7.2 – Solving Quad Equations by Completing the Square**• Solving a Quadratic Equation by Completing the Square • The coefficient of the second-degree term must equal (positive) 1. If not, divide each side of the equation by its coefficient • Write an equivalent equation in the form x2 + px = q. • Add the square of ½ of the coefficient of the linear term to each side; that is, (½p)2 • The left side is now a perfect square trinomial. Rewrite the left side as a square • Take the square root of each side • Solve for x and simplify, if possible • Check**§7.2 – Solving Quad Equations by Completing the Square**• Examples – Solve the following by completing the square x2 – 6x + 8 = 0 2x2 + 9x = 5 x – 2x2 = 0**TMAT 103**§7.3The Quadratic Formula**§7.3 The Quadratic Formula**• The general quadratic equationcan now be solved by completing the square • This will generate a formula that can be used to solve any quadratic equation • x will be written in terms of a, b, and c**§7.3 The Quadratic Formula**• Solving a Quadratic Equation using the Quadratic Formula • If necessary, write the equation in the form ax2 + bx + c = 0 • Substitute a, b, and c into the quadratic formula • Solve for x • Check**§7.3 The Quadratic Formula**• Examples – Solve the following by using the quadratic formula x2 – 6x + 8 = 0 2x2 + 9x = 5 x – 2x2 = 0**§7.3 The Quadratic Formula**• Consider the quadratic formula • The discriminant provides insight into the nature of the solutions • discriminant**§7.3 The Quadratic Formula**• Discriminant • If b2 – 4ac > 0, there are 2 real solutions • If b2 – 4ac is also a perfect square they are both rational • If b2 – 4ac is not a perfect square, they are both irrational • If b2 – 4ac = 0, there is only one rational solution • If b2 – 4ac < 0, there are two imaginary solutions • Chapter 14**§7.3 The Quadratic Formula**• Examples – How many and what types of solutions do each of the following have? x2 – 2x + 17 = 0 x2 – x – 2 = 0 x2 + 6x + 9 = 0 2x2 + 2x + 14 = 0**TMAT 103**§7.4 Applications**§7.4 Applications**• Examples • The work done in Joules in a circuit varies with time in milliseconds according to the formula w = 8t2 – 12t + 20. Find t in ms when w = 16J. • A rectangular sheet of metal 24 inches wide is formed into a rectangular trough with an open top and no ends. If the cross-sectional area is 70 in2, find the depth of the trough.**TMAT 103**§14.1 Complex Numbers in Rectangular Form**§14.1 – Complex Numbers in Rectangular Form**• Imaginary Unit • In mathematics, i is used • In technical math, i denotes current, so j is used to denote an imaginary number • Rectangular Form of a Complex Number • a is the real component, and bj is the imaginary component**§14.1 – Complex Numbers in Rectangular Form**• Examples – Express in terms of j and simplify**§14.1 – Complex Numbers in Rectangular Form**• Powers of j j = j j2 = –1 j3 = –j j4 = 1 j5 = j j6 = –1 j7 = –j j8 = 1 … Process continues • Powers of j evenly divisible by four are equal to 1**§14.1 – Complex Numbers in Rectangular Form**• Examples – Express in terms of j and simplify**§14.1 – Complex Numbers in Rectangular Form**• Additional Information • Complex numbers are not ordered • “Greater than” and “Less than” do not make sense • Conjugate • The conjugate of (a + bj) is (a – bj)**§14.1 – Complex Numbers in Rectangular Form**• Addition and subtraction • Complex numbers can be added and subtracted as if they were 2 ordinary binomials (a + bj) + (c + dj) = (a + c) + (b + d)j (a + bj) – (c + dj) = (a – c) + (b – d)j**§14.1 – Complex Numbers in Rectangular Form**• Examples – Perform the indicated operation (1 – 2j) + (3 – 5j) (–3 + 13j) – (4 – 7j) (½ – 11j) – (½ – 4j)**§14.1 – Complex Numbers in Rectangular Form**• Multiplication • Complex numbers can be multiplied as if they were 2 ordinary binomials (a + bj)(c + dj) = (ac – bd) + (ad + bc)j**§14.1 – Complex Numbers in Rectangular Form**• Examples – Multiply (1 – 2j)(3 – 5j) (–3 + 13j)(4 – 7j) (½ – 11j)(½ – 4j)**§14.1 – Complex Numbers in Rectangular Form**• Division • Complex numbers can be divided by multiplying numerator and denominator by the conjugate of the denominator**§14.1 – Complex Numbers in Rectangular Form**• Examples – Divide**§14.1 – Complex Numbers in Rectangular Form**• Solving quadratic equations with a negative discriminant • 2 complex solutions • Always occur in conjugate pairs • Use quadratic formula, or other techniques**§14.1 – Complex Numbers in Rectangular Form**• Examples – Solve using the quadratic formula x2 + x + 1 = 0 x2 + 9 = 0**§14.1 – Complex Numbers in Rectangular Form**• Adding complex numbers graphically**§14.1 – Complex Numbers in Rectangular Form**• Subtracting complex numbers graphically