1 / 50

Hollywood High School School for Advanced Studies AP Chemistry Mr. Brombach

Hollywood High School School for Advanced Studies AP Chemistry Mr. Brombach. Unit I Structure of an Atom. Unit I. Schedule ____________________________________________________. Lesson 1.1. Introduction Lesson 1.2 . Composition of an Atom. Isotopes

yan
Télécharger la présentation

Hollywood High School School for Advanced Studies AP Chemistry Mr. Brombach

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Hollywood High School School for Advanced Studies AP Chemistry Mr. Brombach

  2. Unit I Structure of an Atom

  3. Unit I.Schedule____________________________________________________ Lesson 1.1. Introduction Lesson 1.2. Composition of an Atom. Isotopes Lesson 1.3. The Nature of Light. Electromagnetic Spectrum Lesson 1.4. Bohr’s Model of an Atom. Wave- Particle Nature of an Electron Lesson 1.5. Orbitals. Quantum Numbers. Lesson 1.6. PracticeQuantum Numbers Lesson 1.7. Unit Review Lesson 1.8. Test # 1

  4. Lesson 1.1. Introduction ____________________________________________________________________________________ • Go to Hollywood HS website • Open Mr. Brombach’s web log: • Go to AP-Chemistry • Find the following: • Syllabus • Unit schedule • HW assignments • Handouts • Lecture notes • Lab Assignments

  5. HW Format____________________________________________ Name_____________________Period____ Date_________ #_____ HW 1.1. # 2.42, p.80 Question……………………………………………………… Answer……………………………………………………….. _______________________________________________ # 2.46, p.80 Question……………………………………………………… Answer……………………………………………………….. _____________________________________________

  6. Lesson 1.2.Composition of an Atom. Isotopes_____________________________________________________________________________________________ MicroworldAtomsMolecules Elements Compounds MacroworldPure Substances Mixtures Matter

  7. Lesson 1.2.Composition of an Atom. Isotopes_____________________________________________________________________________________________ • Physical and chemical properties of a substance depend on its chemical structure • That includes the arrangement of the atoms in a molecule and types of bonding between them

  8. Lesson 1.2.Composition of an Atom _____________________________________________________________________________________________ • Each atom is represented by the notation mass numberA X symbolatomic numberZ • Atomic number (Z) equals the number of protons in the nucleus Z = # p+

  9. Lesson 1.2.Composition of an Atom_____________________________________________________________________________________________ • An atom is neutral (the number of protons equals the number of electrons) # p+ = # e- • Mass number (A) is the total number of protons and neutrons A =# p+ + # no • Number on neutrons can be found from the formula: #no = A - Z

  10. Lesson 1.2.Composition of an Atom_____________________________________________________________________________________________ • Since the mass of an atom is so small, to measure atomic mass we use a group called “Dalton (D)” (the old name amu) 1 D = 1.66 x 10-24 g • Atomic mass in the Periodic Table is done in Daltons • For example, the mass of carbon atom 12 Cis exactly mc = 12 D6 or (12)(1.66 x 10-24 g) = 1.99 x 10-23 g

  11. Lesson 1.2. Isotopes _________________________________________________________________________________ • Not all atoms of a particular element have the same mass • The difference in their mass number (A) is due to the presence of different number of neutrons (no) • For ex.: There are two types of Boron (B) atom: • 10B or Boron – 10 (5 p+ + 5 no) • 11B or Boron – 11 (5 p+ + 6 no)

  12. Lesson 1.2. Isotopes _________________________________________________________________________________ • Isotopes of an element are atoms that have different number of neutrons and, therefore, different mass numbers • An element occurs as a mixture of isotopes • The atomic mass of an element is the average of its isotopic masses according to their natural abundances

  13. Lesson 1.2. Isotopes _________________________________________________________________________________

  14. Lesson 1.2. Isotopes_________________________________________________________________________________ • Find average atomic mass of Mg • Atomic mass portion: 24Mg = 23.9850 x 0.7899 = 18.9458 25Mg = 24.9858 x 0.1000 = 2.4986 26Mg = 25.9826 x 0.1101 = 2.8607 24.3024 D

  15. Lesson 1.3. Nature of Light _________________________________________________________________________________ • How do we know about atoms, as we cannot see them? • To learn about atomic structure, scientists treat matter with different kind of energy (heat, electricity, ionization, magnetic field…) EnergyAn ElementEMR • As a result, the matter gives away electromagnetic radiation (EMR) • By studying EMR, the scientists are able to develop models of the atom

  16. Lesson 1.3. Nature of Light _________________________________________________________________________________ • EMR (light) travels as a wave • It is described by two independent variables: wavelength and frequency • Wavelength (λ – lambda) is the distance (nm) the wave travels during one cycle • Frequency (√ - nu) is the number of cycles the wave undergoes per second (1/s or Hz) • Speed of light in vacuum is constant and equals 3.00 x 108 m/s

  17. Lesson 1.3. Nature of Light _______________________________________________________________________ 750 nm 400 nm

  18. Lesson 1.3. Nature of Light _______________________________________________________________________ • The wavelength is inversely proportional to the frequency Cλ= ----- (1) √ C – speed of light, m/s λ – wavelength, nm √ - frequency, 1/s or Hz

  19. Lesson 1.3. Nature of Light _______________________________________________________________________ • At the beginning of 20th century, the three phenomena involving matter and light could not be explained based on the wave nature of light: • The pattern of intensity and wavelength of light emitted from hot, dense objects (blackbody radiation) • The electric current generated when light shines on a metal plate (photoelectric effect) • The individual colors emitted from electrically (or thermally) excited gases (atomic spectra)

  20. Lesson 1.3. Nature of Light _______________________________________________________________________ • Explaining these phenomena required a radically new view of energy (light): • Plank’s quantum hypothesis (1900) • A beam of light is not a continuous stream of energy; instead the beam consists of zillions of small, discrete packets of energy, each called quantum • Einstein’s particulate nature of light (1905) • The quanta of light behave much like tiny particles of matter, each quantum of light was called a photon

  21. Lesson 1.3. Nature of Light _______________________________________________________________________ • Thus, the light has properties of both, a wave and a particle • To represent this duality, the photon is illustrated as a burst of light with a wave drawn inside the burst • The scientists are free to choose which of these two modes fits their needs the best

  22. Lesson 1.3. Nature of Light _______________________________________________________________________ • The energy carried by the wave is directly proportional to the frequency E = h√ (2) E – energy, J h – Plank’s constant (6.626 x 10-34 J•s) √ - frequency, 1/s or Hz • The most powerful type of EMR are gamma rays that have the highest frequency 2.756 x 102 2.756 x 102

  23. Lesson 1.4. Bohr’s Model of an Atom_______________________________________________________________________ Energy is absorbedEnergy is released• ground stateexcited state • Ground state or stationary state is the most stable (the lowest level of energy) • To move to the higher level an object absorbs energy and turns to excited state (less stable) • To go back to stable state, the object gives away (emits) energy •

  24. Lesson 1.4. Bohr’s Model of an Atom _______________________________________________________________________ • Accepting Plank’s and Einstein’s idea about quantized energy, Bohr proposed that the hydrogen atom had only certain energy levels • If gaseous hydrogen is turned from ground state to excited state by electric discharge, it goes back to ground state by emitting EMR

  25. Lesson 1.4. Bohr’s Model of an Atom _______________________________________________________________________ See p.264 fig. 7.9

  26. Lesson 1.4. Bohr’s Model of an Atom _____________________________________________________

  27. Lesson 1.4. Atomic Spectra _______________________________________________________________________ • As emitted EMR passes through a slit and a prism, the EMR will be divided into individual wavelength • The EMR does not create a continuous spectrum, or rainbow, as sunlight does • Rather, it produces a line spectrum – a series of fine lines of individual colors separated by colorless spaces

  28. Lesson 1.4.Atomic Spectra ___________________________________________________________ • The pattern of wavelength (frequencies) formed by • a given element is referred to as element’s atomic • spectrum • The wavelength at which the colored lines occur • is individual characteristic of the element, its • “fingerprint” that allows to identify an element

  29. Lesson 1.4. Atomic Spectra _______________________________________________________________________ • To find the position and wavelength of any line in a given series, use the Rydberg equation 1 1 1 ------ = R (------ - ------) (3) λ n12 n22 λ – wavelength of a particular spectral line n1, n2 – integers representing energy levels (n2 >n1) R – Rydberg constant = 1.097 x 107 1/m

  30. Lesson 1.3. Bohr’s Model of an Atom_______________________________________________________________________ Lesson 1.4. Bohr’s Model of an Atom______________________________________ ∆ In an atom, an electron can move from one energy level to another only by absorbing or emitting a photon of energy

  31. Lesson 1.4. Bohr’s Model of an Atom _______________________________________________________________________ • The amount of energy an atom emits is the difference between energy of final and initial state ∆ Ephoton = Efin – Ein = = Eexcited state – Egroundstate(4) • The greater the energy level, the greater the energy n E • The energy of any excited state equals: E = -2.18 x 10-18(1/n2), J(5) • The energy emitted of absorbed by H atom ∆E = -2.18 x 10-18(1/nfin2 – 1/nin2) (6)

  32. Lesson 1.5. The Wave-particle Nature of an Electron _______________________________________________________________________ • Does photon have a mass? • The famous Einstein’s equation states the relationship between energy and mass E = mc2(7) E – energy, J m – mass, g c – speed of light, m/s

  33. Lesson 1.5. The Wave-particle Nature of an Electron _______________________________________________________________________ • As light exists as a wave and as a particle, each model has the equation of energy: E = mc2(mass represents a particle) E = h√(frequency represents a wave) mc2 = h√√ = c/λmc2 = hc/λ h m = ----- (8) λc m – mass of photon (EMR or particle)

  34. Lesson 1.5. The Wave-particle Nature of an Electron _______________________________________________________________________ • De Broglie proposed the equation, which connects wave and particle properties of any object such as planet, baseball, or electron h λ = ----- (9) m v v – velocity (speed), m/s • Since electron moves with a speed close to the speed of light, it also exists as a wave and as a particle (duality)

  35. Lesson 1.5. The Atomic Orbital _______________________________________________________________________ • If an electron has the properties of both a particle and a wave, what can we determine about its position in the atom? • The Heisenberg’s Uncertainty Principle states that it is impossible to know simultaneously the exact position and velocity of a particle • That means that we cannot prescribe exact paths for electrons, such as the circular orbits of Bohr’s model

  36. Lesson 1.5. The Atomic Orbital _______________________________________________________________________ • The wave motion of objects on the atomic scale is examined in the field of quantum mechanics • In 1926, Schrodinger formulated an equation from which the probability of finding the electron in hydrogen atom could be determined • If we could plot the positions of an electron of a given energy over time as a series of tiny dots, the resulting pattern would resemble what is called a probability cloud

  37. Lesson 1.5. The Atomic Orbital _______________________________________________________________________ • The electron density diagram represents the probability of finding the electron at a particular point at a given distance r along a line from the nucleus outward • The probability of the electron being far from the nucleus is very small, but not zero • An atomic orbital, like a probability cloud, specifies a volume of space where the electron is most likely to be found

  38. Lesson 1.5. The Atomic Orbital _______________________________________________________________________

  39. Lesson 1.5. The Atomic Orbital _______________________________________________________________ S-orbital (1)

  40. Lesson 1.5. The Atomic Orbital _______________________________________________________________ p-orbital (3)

  41. Lesson 1.5. The Atomic Orbital _______________________________________________________________ d-orbital (5)

  42. Lesson 1.5. The Atomic Orbital _______________________________________________________________ f-orbital (7)

  43. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________ • Each orbital can be described by a set of characteristics called quantum numbers (QN): • n – principal QN (characterizes energy level and size of the orbital) • l – azimuthal QN (energy sublevel and shape) • ml – magnetic QN (orientation in space)

  44. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________ Values Principal QN n = 1, 2, 3, 4, 5 … The greater the “n” value, the higher energy level and the bigger the orbital 5 4 3 2 1

  45. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________ Values Azimuthal QN: “l” = 0, 1, 2, 3, 4…. n-1 • “l” represents: • Energy sublevels: l = 0(s); l = 1(p); l = 2(d); l = 3(f) • Shape of the orbital: s – sphere; p – double-lobe d and f – shape varies f d p s sublevels Energy level

  46. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________ Values Magnetic QN: “ml” = -l…0…+l “ml”represents the orientation of the orbital in space: • l = 0 ml = 0 (only 1 orientation) • l = 1 ml = -1, 0, +1 (3 orientations x, y, z) • l = 2 ml = -2, -1, 0, +1, +2 (5 orientations) • l = 3 ml = -3, -2, -1, 0, +1, +2, +3 (7 orientations)

  47. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________ -On a particular energy level, there are: • 1 s-orbital • 3 p-orbitals • 5 d-orbitals • 7 f-orbitals

  48. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________

  49. Lesson 1.6.Quantum Numbers _________________________________________________________________________________________ Lesson 1.5.a. The Atomic Orbital _______________________________________________________________ l 2px l n ml

  50. Lesson 1.6.Quantum Numbers_________________________________________________________________________________________ • The total number of orbitals on a particular energy level equals: # orbitals = n2 4f 4d 4p 4s 42 = 16 orbitals n = 4 3d 3p 3s n = 3 32 = 9 orbitals 2p 2s n = 2 22 = 4 orbitals 1s n = 1 12 = 1 orbital

More Related