1 / 24

PRISMS

PRISMS. PARTS of a PRISM. FACE. BASE. HEIGHT. FACE. BASE. HEIGHT. TOTAL SURFACE AREA. The sum of the areas of each face. T.A. = ph + 2B p = perimeter of the base h = height of the prism. VOLUME of a PRISM. V = Bh B = area of the Base h = height of the prism.

yen-doyle
Télécharger la présentation

PRISMS

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. PRISMS

  2. PARTS of a PRISM FACE BASE HEIGHT FACE BASE HEIGHT

  3. TOTAL SURFACE AREA The sum of the areas of each face. T.A. = ph + 2B p = perimeter of the base h = height of the prism

  4. VOLUME of a PRISM V = Bh B = area of the Base h = height of the prism

  5. A right triangular prism is shown. Find the total surface area since the volume = 315. T.A. = ph + 2B V= Bh = 315 p = 10.5 + 7 + 6.5 V= (½·10.5·4)h = 315 h = 15 B =½·10.5·4 = 21 V= 21h = 315 T.A. = 24(15) + 2(21) h = 15 T.A. = 402

  6. Parts of a Pyramid

  7. SLANT HEIGHT • The height of the isosceles triangular lateral face

  8. Examples of Pyramids SLANT HEIGHT

  9. TOTAL SURFACE AREA T.A. = ½pl + B p= perimeter of the base l = slant height B = area of the base

  10. VOLUME of a Pyramid V = ⅓Bh B = Area of the base h = height of the pyramid

  11. T.A. = ½pl + B V = ⅓Bh V = ⅓Bh p = 14(4) = 56 l = 24 B = 14(14) = 196 • Find the total surface area and volume of the pyramid. ⅓(196)(20) B = 14 (14) = 196 1306.66666 h = 20 T.A. = ½(56)(24) + 196 = 868 24 m 20 m 25 m

  12. Cylinders Base is always a circle

  13. Parts of a CYLINDER

  14. TOTAL SURFACE AREA T.A. = 2пrh + 2B r = radius of the base h = height of the cylinder B= area of the base

  15. VOLUME of a Cylinder V = пr2h r = radius of the base h = height of the cylinder

  16. Find the total surface area and volume. 7 in V = πr 2h T.A. = 2пrh + 2B V = π(7) 2 (24) h = 24 24 in r = 7 V = 1176 π B = πr2= π(7)2 = 49π T.A. = 2π(7)(24) + 2(49π) T.A. = 336π + 98π = 434π

  17. CONES

  18. TOTAL SURFACE AREA T.A. = пrl + B r = radius of the base l = slant height of the cone B= area of the base

  19. VOLUME of a Cone V = ⅓пr2h r = radius of the base h = height of the cone

  20. Find the total surface area and volume. V = ⅓πr2h T.A. =πrl + B V = ⅓π(82)15 B = 82 π = 64π 17 meters V = 320π T.A. = π(8)(17) + 64π T.A. = 136π + 64π T.A. =200π 16 meters

  21. Spheres

  22. TOTAL AREA T.A. = 4пr2 r = radius of the sphere

  23. VOLUME of a Sphere V = 4/3 пr3 r = radius of the sphere

  24. A basketball has a diameter of about 9 inches. What is the total area and volume of the basketball? T.A. = 4πr2 T.A. = 4π(9/2)2 T.A. = 81π V = 4/3 πr3 V = 4/3 π(9/2)3 V = 121.5π

More Related