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Exploring Fractal Dimensions and the Contributions of Felix Hausdorff

This presentation delves into the pioneering work of Felix Hausdorff in topology and set theory, focusing on his concept of fractal dimension. Learn about Hausdorff’s proof regarding the relationship between aleph numbers and his contributions to metric spaces. We will explore the implications of fractal dimensions, how to calculate the d-dimensional area of fractals, and the critical value that separates infinite areas from those that are zero. Engage in hands-on experiments using transformations and investigate the fascinating world of fractals through a project presentation.

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Exploring Fractal Dimensions and the Contributions of Felix Hausdorff

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  1. Governor’s School for the Sciences Mathematics Day 10

  2. MOTD: Felix Hausdorff • 1868 to 1942 (Germany) • Worked in Topology and Set Theory • Proved that aleph(n+1) = 2aleph(n) • Created Hausdorff dimension and term ‘metric space’

  3. Fractal Dimension • A fractal has fractional (Hausdorff) dimension, i.e. to measure the area and not get 0 (or length and not get infinity), you must measure using a dimension d with 1 < d < 2

  4. Fractal Area • Given a figure F and a dimension d, what is the d-dim’l area of F ? • Cover the figure with a minimal number (N) of circles of radius e • Approx. d-dim’l area is Ae,d(F) = N.C(d)edwhere C(d) is a constant (C(1)=2, C(2)=p) • d-dim’l area of F : Ad(F) = lime->0 Ae,d(F)

  5. Fractal Area (cont.) • If d is too small then Ad(F) is infinite, if d is too large then Ad(F) =0 • There is some value d* that separates the “infinite” from the “0” cases • d* is the fractal dimension of F

  6. Example Let A be the area of the fractalThen since each part is the image of the whole under the transformation:A = 3(1/2)dASince we don’t want A=0, we need 3(1/2)d = 1 or d = log 3/log 2 = 1.585

  7. Example (cont.) • Unit square covered by circle of radius sqrt(2)/2 • 3 squares of size 1/2x1/2 covered by 3 circles of radius sqrt(2)/4 • 9 squares of size 1/4x1/4 covered by 9 circles of radius sqrt(2)/8 • 3M squares of size (1/2) M x(1/2)M covered by 3M circles of radius sqrt(2)/2M+1 • Area: C(d*)3M (sqrt(2)/2M+1)d* = C(d*) (sqrt(2)/2)d* = C(d*) 0.5773

  8. Twin Christmas Tree 3-fold Dragon d* = log(3)/log(2) d* = 2 Sierpinski Carpet Koch Curve d* = log(4)/log(3) d* = log(8)/log(3)

  9. MRCM revisited • Recall: Mathematically, a MRCM is a set of transformations {Ti:i=1,..,k} • This set is also an Iterated Function System or IFS • Difference between MRCM and IFS is that the transformations are applied randomly to a starting point in an IFS

  10. Example IFS (Koch) 1. Start with any point on the unit segment2. Randomly apply a transformation3. Repeat

  11. Fern

  12. Better IFS • Some transformations reduce areas little, some lots, some to 0 • If all transformations occur with equal probability the big reducers will dominate the behavior • If the probabilities are proportional to the reduction, then a more full fractal will be the result

  13. Fern (adjusted p’s)

  14. Lab • Use your transformations in a MRCM and an IFS • Experiment with other transformations

  15. Project • Work alone or in a team of two • Result: 15-20 minute presentation next Thursday • PowerPoint, poster, MATLAB, or classroom activity • Distinct from research paper • Topic: Your interest or expand on class/lab idea • Turn in: Name(s) and a brief description Thursday

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