1 / 2

Endmill Tool Deflection

Endmill Tool Deflection. Su- jin Kim GNU, Korea 2012.11. Endmill Tool Deflection. Spindle speed S12000 rpm Feedrate F3000 mm/min Axial depth of cut d=1 mm Tool Diameter D=12 mm Tool length L=60 mm E = 500 GPa (WC). δ=250 0.06^3 / (3 500 10^9 1.02 10^-9) = 3.5 10^-5 = 3.5 μ m . L.

berg
Télécharger la présentation

Endmill Tool Deflection

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. EndmillTool Deflection Su-jinKim GNU, Korea 2012.11.

  2. EndmillTool Deflection Spindle speed S12000 rpm Feedrate F3000 mm/min Axial depth of cut d=1 mm Tool Diameter D=12 mm Tool length L=60 mm E = 500 GPa (WC) δ=250 0.06^3 / (3 500 10^9 1.02 10^-9) = 3.5 10^-5 = 3.5 μm L I=3.14 0.012^4 / 64 = 1.02 10^-9 A A F = u A = 5σ A = 5 400 MPa 0.125 0.125 mm2 = 250 N F A= ft d = 0.125 mm 1 mm = 0.125 mm2 ft = F(mm/min) / S(rev/min)n(teeth/rev) = 3000/12000*2 = 0.125 (mm/teeth) δ D

More Related