1 / 93

Unghiul a doua drepte in spatiu

Unghiul a doua drepte in spatiu. Probleme by Todor Alex. Problema 1. Fie cubul ABCDEFGH. Sa se determine: a) m<(BG, AD); m<(BG, AE); b) m<(BG, DC); c) m<(AH, GD); d) tg<(BH, DC); e) m<(BH, AF); f) m<(AH, FC);

nia
Télécharger la présentation

Unghiul a doua drepte in spatiu

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Unghiul a doua drepte in spatiu Probleme by Todor Alex

  2. Problema 1 Fie cubul ABCDEFGH. Sa se determine: a) m<(BG, AD); m<(BG, AE); b) m<(BG, DC); c) m<(AH, GD); d) tg<(BH, DC); e) m<(BH, AF); f) m<(AH, FC); g) sin<(FD, EC).

  3. 1.a1) m<(BG, AD) = ?

  4. 1.a1) AD | | BC m<(BG, AD) = m<(BG, BC) = m<(CBG)

  5. 1.a1) m<(BG, AD) = m<(CBG) = 45o

  6. 1.a2) m<(BG, AE) = ?

  7. 1.a2) AE | | BF m<(BG, AE) = m<(BG, BF) = m<(FBG)

  8. 1.a2) m<(BG, AE) = m<(FBG) = 45o

  9. 1.b) m<(BG, DC) = ?

  10. 1.b) DC | | AB m<(BG, DC) = m<(BG, AB) = m<(ABG)

  11. 1.b) m<(BG, DC) = m<(ABG) = 90o

  12. 1.c) m<(AH, GD) = ?

  13. 1.c) AH | | BG m<(AH, GD) = m<(BG, GD) = m<(BGD)

  14. 1.c) m<(AH, GD) = m<(BGD) = 60o

  15. 1.d) tg<(BH, DC) = ?

  16. 1.d) DC | | AB tg<(BH, DC) = tg<(BH, AB) = tg<(ABH)

  17. 1.d) tg<(BH, DC) = tg<(ABH) = AH/AB =

  18. 1.e) m<(BH, AF) = ?

  19. 1.e) AF | | BI m<(BH, AF) = m<(BH, BI) = m<(HBI)

  20. 1.e) BI=a ; BH=a ; HI=a ; => BI2+BH2=HI2 m<(BH, AF) = m<(HBI) = 90o

  21. 1.f) m<(AH, FC) = ?

  22. 1.f) AH | | BG m<(AH, FC) = m<(BG, FC) = m<(FOG)

  23. 1.f) m<(AH, FC) = m<(FOG) = 90o

  24. 1.g) sin<(FD, EC) = ?

  25. 1.g) sin<(FD, EC) = sin(EOF)

  26. 1.g) A(EOF) = EF . OM/2 = sin<(FD,EC)=sin<(EOF)=

  27. Problema 2 Fie paralelipipedul dreptunghic ABCDEFGH cu AB = a, BC = a , AE= a . Determinati: a) m<(HC, AD); b) m<(HC, AB); c) m<(HC, AE); d) tg<(HB, AE); e) m<(HB, AD).

  28. 2.a) m<(HC, AD) = ?

  29. 2.a) AD | | EH m<(HC, AD) = m<(HC, EH) = m<(CHE)

  30. 2.a) m<(HC, AD) = m<(CHE) = 90o

  31. 2.b) m<(HC, AB) = ?

  32. 2.b) AB | | CD m<(HC, AB) = m<(HC, CD) = m<(HCD)

  33. 2.b) m<(HC, AB) = m<(DCH) = 45o

  34. 2.c) m<(HC, AE) = ?

  35. 2.c) AE | | DH m<(HC, AE) = m<(HC, DH) = m<(DHC)

  36. 2.c) m<(HC, AE) = m<(DHC) = 45o

  37. 2.d) tg<(HB, AE) = ?

  38. 2.d) AE | | DH tg<(HB, AE) = tg<(HB, DH) = tg<(DHB)

  39. 2.d) DBAD, m(<A) = 90o => BD = a tg<(HB, AE) = tg<(DHB) = BD/DH =

  40. 2.e) tg<(HB, AD) = ?

  41. 2.e) AD | | BC m<(HB, AD) = m<(HB, BC) = m<(HBC)

  42. 2.e) m<(HB, AD) = m<(HBC) = 45o

  43. Problema 3 Fie tetraedrul regulat (piramida triunghiulara cu toate fetele triunghiuri echilaterale) VABC este M mijlocul lui AC. Determina\i: a) sin<(VM, BC); b) m<(VC, AB).

  44. 3.a) sin<(VM, BC) = ?

  45. 3.a) MN | | BC sin<(VM,BC) = sin<(VM,MN)= sin<(VMN)

  46. 3.a) VP2 = VM2 – MP2 => VP = sin<(VM,BC)=sin<(VMP)=VP/VM=

  47. 3.b) m<(VC, AB) = ?

  48. 3.b) AB | | MQ ; VC | | MR m<(VC, AB) = m<(MR, MQ) = m<(RMQ)

  49. 3.b) RQ2 = VQ2 – VR2 => RQ2 = VQ2 – VR2 m<(VC, AB) = m<(RMQ) = 90o

  50. Problema 4 • In piramida patrulatera regulata VABCD se stie ca VB = AB = a cm ]i M, N sunt mijloacele lui BC, AD. Determinati: • m<(VB, DC); • b) m<(VA, VC); • c) sin<(VM, AC); • d) sin<(VM, VN).

More Related