SlideServe
Menu
Préférences
© SlideServe · v2026

Electric Potential Difference

aidan-neal avatar
13 diapositives · 344 Views · Nov 14, 2014

Electric Potential Difference. Electric Potential Energy (PE). Potential energy associated with a charged object due to its position relative to a source of electric force. Changing the position of the charge in the electric field changes its PE. A larger test charge has a greater PE.

Electric Potential Difference - slide 1
01 / 13Electric Potential Difference
1 / 17

Télécharger la présentation

Electric Potential Difference
Une image / un lien ci-dessous est fourni (tel quel) pour télécharger la présentation

Politique de téléchargement : le contenu du site vous est fourni TEL QUEL pour votre information et votre usage personnel ; il ne peut être vendu, concédé sous licence ni partagé sur d’autres sites sans l’accord de son auteur.Le contenu vous est fourni TEL QUEL, pour votre information et votre usage personnel uniquement. Téléchargez la présentation en cliquant sur ce lien. Lors du téléchargement, si vous ne parvenez pas à télécharger une présentation, l’éditeur a peut-être supprimé le fichier de son serveur.Pendant le téléchargement, si vous ne parvenez pas à obtenir une présentation, le fichier a peut-être été supprimé par l’éditeur.

F I N

Plus de contenu associé

Transcription de la présentation
  1. Electric Potential Difference

  2. Electric Potential Energy (PE) • Potential energy associated with a charged object due to its position relative to a source of electric force. • Changing the position of the charge in the electric field changes its PE. • A larger test charge has a greater PE

  3. Electric Potential Difference (∆V) • The work done moving a charged particle divided by the charge of the particle. • As the value of a charge in a field increases, the value of PE also increases. Electric potential difference is independent of charge at a given point. ∆V = Won q / q • Units = J/C = Volts (V)

  4. Electric Potential Difference (∆V) • The sign of the charge and the direction of the field determines if ∆V is positive or negative. • ∆V is negative if the charge is moved in the same direction as the net force (negative work done). • ∆V is positive if the charge is moved opposite the direction of the net force (positive work done). • ∆V is zero if the charge is moved perpendicular to field lines (no work done). These points are called equipotentials.

  5. Some Points to Remember: • Electric potential difference is also called potential difference or voltage. • The potential difference between two points can be measured using a voltmeter. • The zero point for potential can be arbitrarily assigned. • Points that are grounded are usually assigned a potential of zero.

  6. V = (Vb – Va) = Won q / q = (Fd) / qF=Eq = (Eq)d /q V = Ed d = displacement parallel to the field lines A +q B Electric Potential Difference in a Uniform Field E d

  7. Electric Potential Difference in a Uniform Field • Charges that move parallel to the field lines experience changes in potential. • Charges that move perpendicular to the field lines do not experience changes in potential. • NOTE:A potential difference exists between points in a field even if there is no charge at those points.

  8. Given: E = 1.0 x 103 N/C d = 2.0 m Find: ΔV = ? V = Ed = (1.0 x 103 N/C)(2.0 m) = 2.0 x 103 V A charge moves 2.0 m parallel to the direction of a uniform electric field with a field strength of 1.0 x 103 N/C. What potential difference does the charge move through?

  9. Robert A. Millikan’s Oil Drop Experiment (1909) • Millikan found that charge always occurred in multiples of 1.60 x 10-19 C (the elementary charge) • He concluded that charge is quantized

  10. Capacitor • A device that stores electric energy and electric charge. • Made of 2 conducting plates separated by some distance, each with equal but opposite charge. • Insulating material is often placed between the plates.

  11. Capacitance (C) • The ability of a capacitor to store energy. It is the ratio of the amount of charge stored on each plate to the potential difference between the plates. C = q / ∆V • Units = farads (F) 1 F = 1 C / V • Since farads are large, microfarads (F) or picofarads (pF) are used. (1 pF = 10-12 F)

  12. Some Uses for Capacitors

  13. Given: C = 10. F = 10. x 10 -6 F ∆V = 6000. V Find: q =? C = q /∆V C(∆V) = q = (10. x 10 -6 F )(6000. V) = 0.060 C In a defibrillator, a 10. F capacitor is connected to a potential difference of 6000. V.What is the charge stored in the capacitor?