1 / 14

640 251 Instrumentation for Scientists

640 251 Instrumentation for Scientists. Lecture 9 Operational Amplifier Circuits Inverting Amplifier Non-Inverting Amplifier Instrumentation Amplifier Electro-Cardiogram Amplifier Geoff Taylor & Paul Main. Operational Amplifiers (1). Ideal Operational Amplifiers (2).

akina
Télécharger la présentation

640 251 Instrumentation for Scientists

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 640 251 Instrumentation for Scientists Lecture 9 Operational Amplifier Circuits • Inverting Amplifier • Non-Inverting Amplifier • Instrumentation Amplifier • Electro-Cardiogram Amplifier Geoff Taylor & Paul Main

  2. Operational Amplifiers (1)

  3. Ideal Operational Amplifiers(2) • To simplify design calculations, the following characteristics are assumed for an ideal operational amplifier (abbreviated op. amp.): • Open-loop gain = infinity • Input impedance Rd = infinity • Output impedance Ro = 0 • Bandwidth = infinity (infinite frequency response) • vo = 0 when V1 = V2 (no offset voltage)

  4. Ideal Operational Amplifiers(3) • Rule 1. When the op amp is in the linear range the two inputs are at the same voltage. • Rule 2. No current flows into either terminal of the op amp.

  5. Inverting Amplifier • Inverting Amplifier Vo = - (Rf / Ri) Vi

  6. Non Inverting Amplifier • Non-Inverting Amplifier Vo = Vi . (Rf + Ri)/(Ri)

  7. Differential Amplifier

  8. Instrumentation Amplifier

  9. Instrumentation Amplifier Analysis 1 • First Stage: • In this example R2=R3=10K • Using Superposition Step 1: Set V2 = 0 => V+ = V1(R2+R1)/R1 = 11 V1 V- = –V1(R3/R1+R2) = -10 V1 Step 2: Set V1 = 0 => V+ = –V2(R2/R1+R3)= -10 V2 V- = V2(R2+R1)/R1 = 11 V2 Common Mode Transfer Function: Set V1 = V2. V+ = 11V1 – 10 V2 = V1 V- = 11V2 – 10 V1 = V2 Differential Transfer Function: V+ - V- = 21 (V1 – V2)

  10. Instrumentation Amplifier Analysis 2 • Second Stage – Differential Amplifier • VOut = (V+ - V-) Rf/Ri VOut = 10 (V+ - V-) = 210 (V1 – V2) Providing both V1 & V2 remain within the linear input & output range of the op amp. (typically a volt less than +15V .. -15V power supply range)

  11. Instrumentation Amplifier Features The instrumentation amplifier is unique because it can reject a signal such as 50-Hz mains noise that is common to both inputs. The input impedance is 2 x input impedance of the op amp. For a FET input op amp – input resistance is close to infinity. The insulating gate oxide layer can be damaged by high voltages, so some protection may be required.

  12. Instrumentation Amplifier CMRR The equation for the differential amplifier shows that if the two inputs are driven by the same voltage source (common-mode voltage = CMV =V1 = V2) then Vo = 0 If differential voltage gain (DG) is equal to Rf/Ri. In practice the instrumentation amplifier cannot perfectly reject the common-mode voltage. A quantitative measure of the ability of the differential amplifier to reject common-mode voltage is called the common-mode rejection ratio (CMRR). Typical Values are 100 to 10000 or 40dB to 80dB.

  13. Instrumentation Amplifier CMRR • Common Mode Rejection Ratio (CMRR) = • Differential Mode Gain / • Common Mode Gain • Often expressed as a ratio or in dB

  14. Electro Cardiogram Amplifier

More Related