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This document explores the relationship between pendulum motion and arc distance, emphasizing the close approximation of arc and straight distances within 1%. It utilizes trigonometric functions and rotational formulas to derive key equations such as ( F = mg sin(q) ) and ( T = 2pi sqrt{m/g} ). With practical examples and calculations for a pendulum at a 5° arc, this guide serves as a valuable resource for those studying dynamics and forces in physics.
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q L therefore, the arc distance is within 1% of the straight distance (dottted line) (see next page) T x mg Cos q mg Sin q mg T= 2p m/k From SHM T = 2p m mg/L = 2p L/g f = 1 g/L 2p F = mg Sin q for @5o of arc Sin q =.087 F = mg Sinq = mg q Sin q = x/L x = Sin q L Sin q = q x = q L q = x/L F = mg(x/L) or, F = (mg/L)x F = kx k = mg/L
q Pendulum with 5o arc or less L = 1.0 m Trig. Functions for triangles Rotational formulas for circles L q q 5o (1 rad/57.3O) = .0873 rad L L x x Sin 5o = x/1.0 m x = Sin 5o(1.0 m) x = .0872 m q = x/L x = .0873 rad(1.0 m) x = .0873 m