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Figure 2.1a

Technology 2.1. Evaluating Expressions. Figure 2.1a. For Figure 2.1a,. To evaluate an algebraic expression, we may substitute the value(s) in place of the variable(s) and evaluate the numeric expression. Be sure to enclose the values substituted in parentheses. (. 3. ). x 2. -. 4. (.

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Figure 2.1a

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  1. Technology 2.1 Evaluating Expressions Figure 2.1a For Figure 2.1a, To evaluate an algebraic expression, we may substitute the value(s) in place of the variable(s) and evaluate the numeric expression. Be sure to enclose the values substituted in parentheses. ( 3 ) x2 - 4 ( 1 ) ( 2 ) ENTER ( (-) 5 ) x2 - 4 ( 1 ) ( 2 ) ENTER 1 of 3

  2. Evaluating Expressions Technology 2.1 Figure 2.1b For Figure 2.1b, To evaluate an algebraic expression, we may store the value for the variables and enter the algebraic expression. For ease in reading, we will enter all of these commands as one entry. To do so, we separate each entry with a colon, . Store the three values for a, b, and c separated by colons. ALPHA : 1 ► ALPHA A ALPHA : 3 ► ALPHA B ALPHA : 2 ► ALPHA C ALPHA : Enter the expression. ALPHA B x2 - 4 ALPHA A ALPHA C ENTER 2 of 3

  3. Technology 2.1 Evaluating Expressions Figure 2.1b In order to enter the second expression without retyping, recall the previous entry and edit it. Press to recall the previous entry. Then edit the previous entry, using the arrow keys in combination with delete, , and insert . 2nd ENTRY 2nd INS DEL Move the cursor to the left, using the arrow keys. Place the cursor on top of the 3 and delete 3, . Insert the new value for b, -5, 2nd ENTRY DEL 2nd INS (-) 5 ENTER 3 of 3

  4. Technology 2.2 Testing Algebraic Equations Determine whether x = 5 is a solution of the equation 4x - 3 = 3x + 2. For Figure 2.2a, Figure 2.2a Check the value given by evaluating the expression on the left and the expression on the right. Store the given value for the variable, x = 5. 5 ► X,T,,n Separate the entries. ALPHA : Enter the right side and the left side separately. 4 X,T,,n - 3 ENTER Since 17 = 17, x = 5 is a solution. 3 X,T,,n + 2 ENTER 1 of 2

  5. Technology 2.2 Testing Algebraic Equations Determine whether x = 5 is a solution of the equation 4x - 3 = 3x + 2. For Figure 2.2b, Figure 2.2b Check the value by using the TEST function of the calculator. Store the given value for the variable, x = 5. 5 ► X,T,,n Separate the entries. ALPHA : Enter the the equation. The equals sign is under TEST menu option 1. 4 X,T,,n - 3 2nd TEST 1 3 X,T,,n + 2 ENTER The calculator returns a 1 to indicate that the equation is true and returns a 0 to indicate that the equation is false. Since the calculator returned a 1, x = 5 is a solution of the equation. 2 of 2

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