120 likes | 232 Vues
In this lecture, we dive into the ideal op-amp model, exploring crucial conditions such as equal input currents (i+ = i- = 0) and voltage levels (v+ = v-). We utilize Kirchhoff's Current Law (KCL) at the inputs to analyze op-amp circuits and derive the output voltage. Special attention is given to the voltage follower configuration, illustrating its relationship between output (vout) and input (vin) voltages. We also compare A/D converter performance with and without a voltage follower, clarifying its importance in sensor applications.
E N D
More On Op Amps Lecture 25
Review • The ideal op amp model leads to the following conditions: i+ = i- = 0 v+ = v- • The op amp will set the output voltage to whatever value results in the same voltages at the inputs. Lecture 25
Review • To solve an op amp circuit, we usually apply KCL at one or both of the inputs. • We then invoke the consequences of the ideal model. • We solve for the op amp output voltage. Lecture 25
+ - The Voltage Follower + + vin - vout - Lecture 25
Why Use a Voltage Follower? Lecture 25
Rs + + A/D Converter Sensor vs vA/D - - RA/D Without a Voltage Follower vA/D is not equal to vs Lecture 25
+ vs - RA/D With a Voltage Follower vA/D is equal to vs + + - Rs vA/D - Sensor A/D Converter Lecture 25
C R - + + + Vin Vout - - An Integrator Lecture 25
KCL at the Inverting Input C iC(t) R - iR(t) i- + + + vin(t) vout(t) - - Lecture 25
KCL Lecture 25
Solve for vout(t) Lecture 25