1 / 24

Lesson 6-7 Pages 298-302

Lesson 6-7 Pages 298-302. Using Percent Equations. Lesson Check 6-6. What you will learn!. How to solve percent problems using percent equations. How to solve real-life problems involving discount and interest. Vocabulary. What you really need to know!.

Télécharger la présentation

Lesson 6-7 Pages 298-302

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Lesson 6-7Pages 298-302 Using Percent Equations Lesson Check 6-6

  2. What you will learn! • How to solve percent problems using percent equations. • How to solve real-life problems involving discount and interest.

  3. Vocabulary

  4. What you really need to know! In a percent equation, the percent is written as a decimal.

  5. What you really need to know! % of BASE = PART The word “ of ”means multiply!

  6. What you really need to know! The number after the word “of” is the base! The number near the word “is” is the part!

  7. Example 1: Find 38% of 22. % x BASE = PART 38% x 22 = PART 0.38 x 22 = PART 8.36 = PART

  8. Example 2: 19 is what percent of 25? % x BASE = PART % x 25 = 19 % = 19 ÷ 25 76% % = 0.76

  9. Example 3: 84 is 16% of what number? % x BASE = PART 16% x BASE = 84 0.16 x BASE = 84 BASE = 84 ÷ 0.16 BASE = 525

  10. Example 4: The regular price of a ring is $495. It is on sale at a 20% discount. What is the sale price of the ring? 20% x $495 = $99 $495 - $99 = $396

  11. Example 5: Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495? I = prt

  12. I = prt I is interest p is principal r is annual interest rate t is time in years

  13. Example 5: Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495? 495 = 2,000 • 0.045 • t 5.5 years = t

  14. Page 300 Guided Practice #’s 4-11

  15. Read: Pages 298-300 with someone at home and study examples!

  16. Homework: Pages 301-302 #’s 12-40 even #’s 44-61 Lesson Check 6-7

  17. Page 738 Lesson 6-7

  18. Lesson Check 6-7

More Related