1 / 33

SPLASH: S tructural P attern L ocalization A nalysis by S equential H istograms

SPLASH: S tructural P attern L ocalization A nalysis by S equential H istograms. A. Califano, IBM TJ Watson Presented by Tao Tao April 14 th , 2004. Motif: A functional regain of a DNA or protein sequence. Amino Acids sequences. How to discover the functional regains automatically?.

china
Télécharger la présentation

SPLASH: S tructural P attern L ocalization A nalysis by S equential H istograms

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. SPLASH: Structural Pattern Localization Analysis by Sequential Histograms A. Califano, IBM TJ Watson Presented by Tao Tao April 14th, 2004

  2. Motif: A functional regain of a DNA or protein sequence Amino Acids sequences How to discover the functional regains automatically?

  3. Automatic Motif discovery • Problem • Use A, B, C, … stands for different amino acids • A protein sequence: ABABAABCDBAA… • Motifs are certain patterns in sequences for example: ABCA • Previous Methods: small scale discovery • Several sequences  similar functions  alignment • Can we use data mining to generate motifs candidates first?

  4. Automatically discover motifs: What properties should a motif have? • It has a specific function  conservative  frequent appearing in sequences • Evolution  likely not continually identical For example: ABCBABABA AB--ABAB- string matching,suffix tree … AB-BAB-B-  how?

  5. Formal problem definition • Input: A string of characters: S=s1s2,…,sL • Output:A frequent pattern: (∑ U ●)* ●: a wild card to match a single character, ∑: a full character * : repeat arbitrary times Note: NO arbitrary-length gap. ABCD, AED are different

  6. Regular Expression: to describe a certain type of patterns • | or : A|B means A or B • ● wild card to match any characters A●B means: AAB, ABB, ACB, … • * to repeat any times (including 0 times) (AB)* means null, AB, ABAB, ABABAB, … • + to repeat any times (not including 0 times) • …

  7. Any requirements for output patterns? • Can wild card be anywhere? Do we need some constraints on wild cards? • What means “frequent”? • How long should a qualified pattern be?

  8. Can wild card be anywhere? • A pattern can have ●: for example A●BA●●B • But, A●●●●●●●●●●●●●●●●BBA ?? Probably, it cannot be too “sparse”… • Naïve solution: no more than n ● • But, for example n=5 A●●●●●B : 5 ● A●BB●●A●●B●●A : 7●

  9. Two ● at most Density: how “sparse” do we allow? Given a pattern P, any length l0 region in P must have k0 full characters Example: l0 = 5, k0 = 3 s1s2s3s4s5s6s7s8s9……

  10. Two ● at most Density: how “sparse” do we allow? Given a pattern P, any length l0 region in P must have k0 full characters Example: l0 = 5, k0 = 3 s1s2s3s4s5s6s7s8s9……

  11. Two ● at most Density: how “sparse” do we allow? Given a pattern P, any length l0 region in P must have k0 full characters Example: l0 = 5, k0 = 3 s1s2s3s4s5s6s7s8s9……

  12. Density: how “sparse” do we allow? Given a pattern P, any length l0 region in P must have k0 full characters Example: l0 = 5, k0 = 3 s1s2s3s4s5s6s7s8s9…… A●●ABB●A √ BA●●A●BB X

  13. Frequency and length • At least, the patterns have K0 full characters repeating J0times • Example J0 =3 ABCBABABA √ ABCBABABA X • Example K0 =3 ABCBABABA X ABCBABABA √

  14. Summary of parameters for a pattern • Sequence S, and its length L • Pattern P, K full character, appears J times • Length constraints: K ≥K0 • Frequency constraint: J ≥J0 • Density constraint: l0 , k0

  15. Apriori property • A constraint has a-priori property means: If a setviolates this constraint, any its superset will violate this constraint as well. • For example max(S) < 5 • Frequency constraint has a-priori property! For example, BA●A●BB appears less than J0times, any its super patterns CANNOT appears more than J0times!

  16. A whole picture of the algorithm • To form longer pattern only from short qualified patterns. • First, to generate candidates/seed (length l0): every seed should repeat at least J0 times • To generate longer patterns from short patterns, iteratively 1. Two patterns are together 2. Longer patterns repeat at least J0 ……

  17. Generate the seeds: enumerating … • To generate seeds (shortest patterns) first ABAABBCBACBDB… J0=4 A: 4, B: 6, C:2, D: 1 • Are length 1 seeds too short? How long could those seeds be? • Too long: enumerating costs too much time • Too short: maybe not efficient, also not consider the density constraints • Maybe, we should start from the patterns with length l0 .

  18. How to generate seeds with length l0 ? • Give l0 and k0, and character sets ABC… • Enumerating all possible patterns with length l0 • Scan the sequence the count the frequency • For example, l0=3, k0=2, ABC AAA, AAB, AAC, ABA, … AA●, AB●, AC●, … A●A, A●B, A●C, … …

  19. Can we do it more efficiently? • Give l0 and k0, 1: full character 0:wild card Enumerating all possible patterns by 1 and 0? • Example l0=5, k0=3, to find comb 11111, 11110, 11101, 11100, 11011, 11010, 11001, 10111, 10110, 10101 10011, 01111, 01110, 01101, 01011, 00111

  20. A●A●B How to use comb? For example 10101 A B A A B A B B A B A B A B B A A B

  21. B●A●A How to use comb? For example 10101 A B A A B A B B A B A B A B B A A B

  22. A●B●B How to use comb? For example 10101 A B A A B A B B A B A B A B B A A B

  23. How to use comb? For example 10101 A B A A B A B B A B A B A B B A A B A●A●B 3, B●A●A 2, A●B●B 2 B●B●A 2, B●B●B 2, A●A●A 1 A●B●A 1, B●A●B 1 J0 = 3? only A●A●B left By the same way, use others combs to generate other seeds, different combs won’t generate the same patterns

  24. How to get long patterns? • Long pattern  two patterns could be merged  need short patterns and their locations • Pattern: A●B●●C {A:0,B:2,C:5} • Locus: the locations where a pattern occurs: Patten AB in string ABBCABAB Its locus {0, 4, 6}

  25. Append operation: to connect two small patterns to a longer pattern Patten S1: A●●B●C and S2: B●D●  S1S2: A●●B●CB●D● conditional on: Their locus have intersection S1 locus: {1, 20, 32, 57 …} S2 locus: {7, 13, 38, 63 … }  {1,7,32,57,…} S1S2 locus: {1,32,57,…} -6

  26. Add: to make the patterns more “dense” • Patten A●●B●C●●●D and ●●●B●CE  A●●B●CE●●D on the conditions: Their locus (with shifting) have intersection

  27. Significance: whether it can be generated by randomly sampling ? • hypothesis: A pattern is not randomly generated Given: character set: {A,B,C,D,E} sequence length: L A pattern: A●BA●AA●B Its frequency j Probability to generate this pattern j times pure randomly?

  28. Statistical significance • Pure random sampling, the frequency should satisfy normal distribution • Z score, (A-E[A])/σA --- normalized into N(0,1)

  29. Experiments • Two questions to answer. • How efficient is this algorithm? • How effective is this algorithm? • Baseline algorithm • PRATT(EBI), MEME(UCSD)

  30. Efficiency PRATT SPLASH

  31. Effectiveness Search against SWISS-PROT Rel. 36, 578 GPCR proteins returned, only 4 false positive MEME cannot find it, PRATT program crashed

  32. Conclusions • Deterministic algorithm: It can discover all patterns satisfying the requirements • Efficient and scalable: It beats PRATT and MEME. More scalable … • Effective: It can discover useful patterns.

  33. Problems • All problems that A-priori algorithm could have: too many results, cannot really avoid worse-case exponential … • Doesn’t really consider the 3D structure of proteins • The software crashes sometimes

More Related