1 / 8

There are three ratios that you need to learn:

This is opposite the angle. There are three ratios that you need to learn:. This is opposite the right-angle. hypotenuse. opposite. adjacent. This is next to the angle. Remember. Where are the hypotenuse, adjacent and opposite lengths. Finding a length.

clarencen
Télécharger la présentation

There are three ratios that you need to learn:

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. This is opposite the angle. There are three ratios that you need to learn: This is opposite the right-angle hypotenuse opposite adjacent This is next to the angle Remember Where are the hypotenuse, adjacent and opposite lengths.

  2. Finding a length You need to label all the lengths of the triangle. hypotenuse 10cm The adjacent is not needed in this question; the question is only using opposite and hypotenuse. opposite adjacent

  3. Finding a length You need to label all the lengths of the triangle. hypotenuse 10cm The adjacent is not needed in this question; the question is only using opposite and hypotenuse. opposite

  4. Finding a length We need to use the sine ratioand substitute the values/variables that we know. hypotenuse 10cm opposite

  5. Finding a length We need to solve the equation (*). hypotenuse 10cm opposite We can think of this as: OR rearrange the equation (*) by multiplying both sides by x.

  6. These two triangles are very different. The variable x will be on the denominator This is an example of where we have to solve an equation with the variable on the denominator, so multiply both sides by x. still need to get x on its own, so divide both sides by sin30

  7. 2. Pick the correct formula 1. label the triangle 15cm opposite 3. Substitute in the correct values adjacent 4. Rearrange to find x

  8. 15cm opposite adjacent

More Related