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Molarity:

Molarity:. Molarity. Molarity. M. ____________: moles of solute per liter of solution (concentration) _______________ ( ) = moles of solute ÷ Liters of solution Practice Problems: 1. What is the molarity of a solution that contains 5.5 moles of NaCl in 10.5 liters of solutions?.

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Molarity:

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  1. Molarity: Molarity Molarity M • ____________: moles of solute per liter of solution (concentration) • _______________ ( ) = moles of solute ÷ Liters of solution Practice Problems: 1. What is the molarity of a solution that contains 5.5 moles of NaCl in 10.5 liters of solutions? Grams of solute = (M) x (L) x (Molar Mass) Convert mL to L move decimal 3 places to left moles grams X Molarity Liters Molar mass M L X X (M) = 5.5 mol 10.5 liters = 0.52 M

  2. Practice Problems 2. What is the molar concentration of an aqueous NaCl solution when 25.0 grams are dissolved in water to make 500 mL of solution? 3. What is the number of moles of solute in 200 mL of a 0.5 M solution? 4. How many liters of a 0.5 M solution are needed to give 2.5 moles of solute? (M) = 25 grams = (0.500 L) x (58 g/mole) 0.862 M 0.1 mol moles = 0.5 M x .2 L = Liters = 2.5 moles = .5 M 5.0 L

  3. Making a Solution of a Required Concentration # of moles ÷ # of liters = Molarity

  4. Making Dilutions less adding solvent • Dilution: Making a solution _______ concentrated by ________ more ___________ . Important: When diluting acids: “Add acid to water, do as you ought-er.” A in W M1xV1=M2xV2 M1 -- the initial concentration of the solution. V1 -- the initial volume of the original solution that is going to be diluted with water. M2 -- the final concentration of the solution after it’s diluted with water. V2 -- the total volume of the final solution after it has been diluted with water.

  5. Making Dilutions M1xV1=M2xV2 Practice Problems: 1) The science department buys HCl in large bottles that have a concentration of 12 Molar. The science teacher then dilutes the acid for labs. How would the teacher make 2.0 liters of a 2.5 M HCl solution from this “stock” solution? 2) What is the final concentration of a sugar solution if 300 mL of water is added to 500 mL of a 2.5 M sugar solution? ( ) ( ) = ( ) ( ) 12 M V1 2.5 M 2.0 L V1 = 0.417 L Take 0.417 L of the stock solution and add it to some water and then add enough water to make a final volume of 2.0 liters. ( ) ( ) = ( ) ( ) 2.5 M 500 mL M2 300 mL M2 = 4.17 M

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