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cweathers
38 diapositives · 496 Views · Jan 04, 2020

Find: ω d. rad. s. damping data. machine. vertical. j. u j. oscillations. w = 250 [lb f ]. 0. 0.8 [in]. 2. 0.1 [in]. damper. 3 22 48 176. Find: ω d. rad. s. damping data. machine. vertical. j. u j. oscillations. w = 250 [lb f ]. 0. 0.8 [in]. 2. 0.1 [in]. damper.

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  1. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper • 3 • 22 • 48 • 176

  2. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper • 3 • 22 • 48 • 176

  3. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper • 3 • 22 • 48 • 176

  4. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper ωd=ωn* 1-ζ2 damped natural frequency

  5. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper ωd=ωn* 1-ζ2 damped undamped natural natural frequency frequency

  6. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper ωd=ωn* 1-ζ2 damping ratio damped undamped natural natural frequency frequency

  7. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper ωd=ωn* 1-ζ2 damping ratio damped undamped natural natural frequency frequency [rad/s] [rad/s]

  8. Find:ωd rad s damping data machine vertical j uj oscillations w=250[lbf] 0 0.8[in] 2 0.1[in] damper ωd=ωn* 1-ζ2 damping ratio damped undamped natural natural frequency frequency [rad/s] [rad/s]

  9. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper k ωn= m damping data j uj 0 0.8[in] 2 0.1[in]

  10. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k stiffness ωn= in m damping data j uj 0 0.8[in] 2 0.1[in]

  11. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k stiffness ωn= in m lbf*s2 mass damping data in j uj 0 0.8[in] 2 0.1[in]

  12. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k stiffness ωn= in m lbf*s2 mass damping data in j uj F k= 0 0.8[in] Δx 2 0.1[in]

  13. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k stiffness ωn= in m lbf*s2 mass damping data in j uj F k= 0 0.8[in] Δx 2 0.1[in]

  14. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k stiffness ωn= in m lbf*s2 mass damping data in j uj F k= 0 0.8[in] Δx 2 0.1[in]

  15. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k stiffness ωn= in m lbf*s2 mass damping data in j uj F 250[lbf] lbf k= = =312.5 0 0.8[in] Δx in 0.8[in] 2 0.1[in]

  16. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 mass damping data in j uj 0 0.8[in] 2 0.1[in]

  17. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 mass damping data in j uj 0 0.8[in] 2 0.1[in]

  18. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 mass damping data in j uj F force 0 0.8[in] m= a 2 0.1[in]

  19. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 mass damping data in j uj F force 0 0.8[in] m= a acceleration 2 0.1[in]

  20. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 mass damping data in j uj 250[lbf] F 0 0.8[in] m= = a 386[in/s2] 2 0.1[in]

  21. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 mass damping data in uj i 250[lbf] F lbf*s2 0 0.8[in] m= = =0.648 a in 386[in/s2] 2 0.1[in]

  22. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 0.648 damping data in j uj 0 0.8[in] 2 0.1[in]

  23. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] undampednatural frequency damper lbf k 312.5 ωn= in m lbf*s2 0.648 damping data in j uj rad ωn=21.96 0 0.8[in] s 2 0.1[in]

  24. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] rad 21.96 s damper damping data j uj 0 0.8[in] 2 0.1[in]

  25. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper damping data j uj 0 0.8[in] 2 0.1[in]

  26. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper damping data j uj 0 0.8[in] 2 0.1[in]

  27. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper damping data j uj 0 0.8[in] 2 0.1[in]

  28. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper damping data j uj 0 0.8[in] 2 0.1[in]

  29. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper 1 ui ζ= ln * damping data 2*π*j ui+j j uj 0 0.8[in] 2 0.1[in]

  30. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper 1 ui ζ= ln * damping data 2*π*j ui+j j uj oscillations 0 0.8[in] 2 0.1[in]

  31. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper 1 ui ζ= ln * damping data 2*π*j ui+j j uj maximum oscillations 0 0.8[in] displacement 2 0.1[in] from equilibrium

  32. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper 1 ui ζ= ln * damping data 2*π*j ui+j j uj maximum oscillations 0 0.8[in] displacement 2 0.1[in] from equilibrium

  33. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] damping rad 21.96 ratio s damper 1 ui ζ= ln * damping data 2*π*j ui+j j uj ζ=0.165 0 0.8[in] 2 0.1[in]

  34. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] 0.165 rad 21.96 s damper damping data j uj 0 0.8[in] 2 0.1[in]

  35. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] 0.165 rad 21.96 s damper rad ωd=21.66 s damping data j uj 0 0.8[in] 2 0.1[in]

  36. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] 0.165 rad 21.96 s damper • 3 • 22 • 48 • 176 rad ωd=21.66 s damping data j uj 0 0.8[in] 2 0.1[in]

  37. Find:ωd rad s ωd=ωn* 1-ζ2 machine w=250[lbf] 0.165 rad 21.96 s damper • 3 • 22 • 48 • 176 rad ωd=21.66 s damping data j uj AnswerB 0 0.8[in] 2 0.1[in]

  38. H*C σfinal ( ) ‘ ρcn= log V [ft3] W [lb] 1+e σinitial ‘ A W S d 20 ft 1 Index γclay=53.1[lb/ft3] Find: σ’vρc d = 30 feet (1+wc)*γw wc+(1/SG) σ’v = Σ φ γ Δ d ˚ Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] φ=α1-α2 10 [ft] Clay = γsand dsand +γclay dclay 40 ft text wc = 37% ? Δh 20 [ft] τ [lb/ft2] (5[cm])2*π/4 φ c=0 400 1,400 σ3 Sand σ1