1 / 16

King Fahd University of Petroleum & Minerals

In this lecture by Dr. Meyassar N. Al-Haddad, we explore the essential concepts of planar kinetics of rigid bodies, focusing on work and energy. The lecture covers kinetic energy in general translation, rotation, and general plane motion, providing detailed examples such as the total kinetic energy of a bike and its components. We will also discuss the work done by forces, including springs and constraints. By examining practical examples and theoretical principles, this lecture aims to deepen understanding of mechanical dynamics.

dakota
Télécharger la présentation

King Fahd University of Petroleum & Minerals

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 36

  2. Chapter 18Planar Kinetics of Rigid Bodies:Work and Energy

  3. Kinetic Energy

  4. General Translation Rotation

  5. Rotation

  6. General Plane Motion (Translation and Rotation)

  7. Example Total K.E. ? K.E. of the Body of Bike and man ( translational ) K.E of the wheel ( Translational + Rotational ) Total K.E. = 2 Twheel +T B+Man

  8. mB=6 kg mD=10 kg mC=12 kg No slipping Total K.E = ? Example 18-1 Block (Translation) Disk (Rotation) Cylinder ( Translation &Rotation)

  9. Problem wAB=wCD=10 Ib wBC=20 Ib Total K.E = ?

  10. The work of a force

  11. Work of a Spring Force

  12. Force That Do No Work • Force Perpendicular to the displacement • Weight • Normal reaction Rolling resistance force Fr Fr acts at point which has zero velocity The point is not displaced

  13. Ox Oy On Ot Pin Reaction Pin Reaction Do No work Act on zero velocity and create no displacement

  14. The Work of a couple -Do work only when the body undergoes a rotation -Translation : positive work cancels the negative work -Rotation

  15. Example 18-2 m =10 kg M = 50 NmP = 80N, unstretched 0.5 m total work ?

  16. Thank you

More Related