1 / 29

Geometric Representation of Modulation Signals

Geometric Representation of Modulation Signals. Digital Modulation involves Choosing a particular signal waveform for transmission for a particular symbol For M possible symbols, the set of all signal waveforms are:.

dessa
Télécharger la présentation

Geometric Representation of Modulation Signals

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Geometric Representation of Modulation Signals • Digital Modulation involves • Choosing a particular signal waveform for transmission for a particular symbol • For M possible symbols, the set of all signal waveforms are: • For binary modulation, each bit is mapped to a signal from a signal set S that has two signals. • We can view the elements of S as points in vector space.

  2. Geometric Representation of Modulation Signals • Vector space • We can represent the elements of S as linear combination of basis signals i (t). • The number of basis signals is the dimension of the vector space. • Basis signals are orthogonal to each-other. • Each basis is normalized to have unit energy.

  3. Geometric Representation of Modulation Signals Let {j(t)| j = 1,2,…,N} represent a basis ofSsuch that (1) Any symbol, si(t)  si(t)= (2) Basis signals are orthogonal to each other in time (3) Each basis signal is normalized to have unit energy E = Basis signals  Coordinate system for S Gram-Schmidt process  systematic way to obtain basis for S

  4. Q I Example Two signal waveforms to be used for transmission The basis signal One dimensional Constellation Diagram

  5. Q Q /2 M1 = I  I 0 3/4 /4 3/2 7/4 54 M2 = QPSK Constellation Diagram Rotation by /4 obtain new QPSK signal set Es = 2Eb

  6. binary symbol grey coded QPSK signal si1 si2 10 7π/4 11 5π/4 01 3π/4 00 π/4 binary symbol grey coded QPSK signal si1 si2 10 3π/2 0 11 π 0 01 π/2 0 00 0 0 si(t) = si1,1(t) + si22(t) Signal Space Characterization of QPSK Signal Constellations ithQPSK signal, based on message points (si1, si2) defined in tables for i = 1,2 and 0 ≤ t ≤ Ts

  7. Q = possible states forkfork-1= n/4 = possible states for kfork-1= n/2 I possible signal transitions /4 QPSKmodulation • modulated signal selected from 2 QPSK constellations shifted by /4 • for each symbol  switch between constellations –total of 8 symbols • states 4 used alternately • phase shift between each symbol =nk= /4 , n = 1,2,3 • - ensures minimal phase shift, k= /4 between successive symbols • - enables timing recovery & synchronization

  8. Constellation Diagram • Properties of Modulation Scheme can be inferred from the Constellation Diagram: • Bandwidth occupied by the modulation increases as the dimension of the modulated signal increases. • Bandwidth occupied by the modulation decreases as the signal_points per dimension increases (getting more dense). • Probability of bit error is proportional to the distance between the closest points in the constellation. • Euclidean Distance • Bit error decreases as the distance increases (sparse).

  9. Linear Modulation Techniques • Digital modulation techniques classified as: • Linear • The amplitude of the transmitted signal varies linearly with the modulating digital signal, m(t). • They usually do not have constant envelope. • More spectrally efficient. • Poor power efficiency • Example: QPSK. • Non-linear / Constant Envelope

  10. Constant Envelope Modulation • constant carrier amplitude - regardless of variations in m(t) • Better immunity to fluctuations due to fading. • Better random noise immunity. • improved power efficiency without degrading occupied spectrum • - use power efficient class Camplifiers (non-linear) • low out of band radiation (-60dB to -70dB) • use limiter-discriminator detection • - simplified receiver design • high immunity against random FM noise & fluctuations • from Rayleigh Fading • larger occupied bandwidth than linear modulation

  11. Constant Envelope Modulation • Frequency Shift Keying • Minimum Shift Keying • Gaussian Minimum Shift Keying

  12. Frequency Shift Keying (FSK) • Binary FSK • Frequency of the constant amplitude carrier is changed according to the message state  high (1) or low (0) • Discontinuous / Continuous Phase

  13. input data phase jumps cos w1t switch cos w2t = sBFSK(t)= vH(t) binary 1 binary 0 sBFSK(t)= vL(t) = Discontinuous Phase FSK Switching between 2 independent oscillators for binary 1 & 0 • results in phase discontinuities • discontinuities causes spectral spreading & spurious transmission • not suited for tightly designed systems

  14. Continuous Phase FSK single carrier that is frequency modulated using m(t) sBFSK(t) = = where (t) = • m(t) = discontinuous bit stream • (t) = continuous phase function proportional to integral of m(t)

  15. x a0 a1 0 1 VCO Data 1 1 0 1 FSK Signal 0 1 1 modulated composite signal cos wct FSK Example

  16. complex envelope of BFSK is nonlinear function of m(t) • spectrumevaluation - difficult - performed using actual time • averaged measurements • PSD of BFSK consists of discretefrequency components at • fc • fc nf , n is an integer • PSD decay rate (inversely proportional to spectrum) • PSD decay rate for CP-BFSK  • PSD decay rate for non CP-BFSK  • f = frequency offset fromfc Spectrum & Bandwidth of BFSK Signals

  17. Spectrum & Bandwidth of BFSK Signals • Transmission Bandwidth of BFSK Signals (from Carson’s Rule) • B = bandwidth of digital baseband signal • BT = transmission bandwidth of BFSK signal • BT= 2f +2B • assume 1st null bandwidth used for digital signal, B • - bandwidth for rectangular pulses is given by B = Rb • - bandwidth of BFSK using rectangular pulse becomes • BT = 2(f + Rb) • if RC pulseshaping used, bandwidth reduced to: • BT = 2f +(1+) Rb

  18. General FSK signal and orthogonality • Two FSK signals, VH(t) and VL(t) are orthogonal if ? • interference between VH(t) and VL(t) will average to 0 during • demodulation and integration of received symbol • received signal will contain VH(t) and VL(t) • demodulation of VH(t) results in (VH(t) + VL(t))VH(t) ?

  19. vH(t) = vL(t) = and then and vH(t)vL(t) = = = = An FSK signal for 0 ≤ t ≤ Tb vH(t)vL(t) are orthogonal if Δf sin(4πfcTb) = -fc(sin(4πΔf Tb)

  20. consider binary CPFSK signal defined over the interval 0 ≤ t ≤ T s(t) = • θ(t) = phaseof CPFSK signal • θ(t) is continuous s(t) is continuous at bit switching times • θ(t) increases/decreases linearly with t during T θ(t) = θ(0) ± ‘+’ corresponds to ‘1’ symbol ‘-’ corresponds to ‘0’ symbol h = deviation ratio of CPFSK CPFSK Modulation elimination of phase discontinuity improves spectral efficiency & noise performance 0 ≤ t ≤ T

  21. 2πfct +θ(0) + = 2πf2 t+θ(0) f1 = 2πfct +θ(0) - = 2πf1t+θ(0) fc= f2 = yields and thus h = T(f2 – f1) To determine fc and h by substitution • nominal fc= mean of f1 and f2 • h≡f2 – f1 normalized by T

  22. At t = T θ(T) = θ(0) ± πh kFSK= symbol‘1’  θ(T) - θ(0) = πh symbol‘0’  θ(T) - θ(0) = -πh • peak frequency deviation F = |fc-fi | = ‘1’ sent  increases phase of s(t) by πh ‘0’ sent  decreases phase of s(t) by πh • variation ofθ(t)with t follows a path consisting of straight lines • slope of lines represent changes in frequency FSK modulation index =kFSK (similar to FM modulation index)

  23. θ(t) - (0) rads 3πh 2πh πh 0 -πh -2πh -3πh 0 T 2T 3T 4T 5T 6T t Phase Tree •  depicted from t = 0 • phase transitions across • interval boundaries of • incoming bit sequence • θ(t) - θ(0) = phase of CPFSK signal is even or odd multiple of πh at even or odd multiples of T

  24. θ(t) - (0) 3π 2π π 0 -π -2π -3π 0 T 2T 3T 4T 5T 6T t θ(t) = θ(0) ± 0 ≤ t ≤ T Phase Tree is a manifestation of phase continuity – an inherent characteristic of CPFSK 1 0 0 0 0 1 1 •  thus change in phase over T • is either πor -π • change in phase of π = change in phase of -π • e.g. knowing value of bit i doesn’t help to find the value of bit i+1

  25. fi= nc = fixed integer assume fi given by as si(t) = 0 ≤ t ≤ T for i = 1, 2 si(t) = 0 ≤ t ≤ T for i = 1, 2 = 0 otherwise = 0 otherwise • CPFSK = continuous phase FSK • phase continuity during inter-bit switching times

  26. 1(t) = 2(t) = 0 ≤ t ≤ T 0 ≤ t ≤ T = 0 otherwise = 0 otherwise for i = 1, 2 i(t) = 0 ≤ t ≤ T = 0 otherwise BFSK constellation: define two coordinates as let nc = 2 and T = 1s (1Mbps) then f1= 3MHz,f2 = 4MHz

  27. 0 ≤ t ≤ T s1(t) = = 0 otherwise 0 ≤ t ≤ T = = s2(t) = = 0 otherwise 2(t) 0 1 1(t) BFSK Constellation

  28. cos wct output + - Decision Circuit  r(t) sin wct Probability of error in coherent FSK receiver given as: Pe,BFSK = Coherent BFSK Detector • 2 correlators fed with local coherent reference signals • difference in correlator outputs compared with threshold to • determine binary value

  29. Matched Filter fH Envelope Detector + - r(t)  output Tb Decision Circuit Envelope Detector Matched Filter fL Pe,BFSK, NC = Non-coherent Detection of BFSK • operates in noisy channel without coherent carrier reference • pair of matched filters followed by envelope detector • - upper path filter matched to fH (binary 1) • - lower path filter matched to fL (binary 0) • envelope detector output sampled at kTb compared to threshold Average probability of error in non-coherent FSK receiver:

More Related