1 / 25

N = 5290 Species

drago
Télécharger la présentation

N = 5290 Species

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. rmax, generation time and body sizeExponential population growthDemographic and environmental stochasticityOptimal reproductive tacticsSemelparity versus iteroparityReproductive effort (parental investment)Expenditure per progenyParent-offspring conflictPatterns in Avian Clutch SizesAltrical versus PrecocialNidicolous vs. NidifugousDeterminant vs. Indeterminant LayersOpen Ground NestersOpen Bush Nesters Open Tree Nesters Hole NestersNest attentiveness and male feedingFlicker egg removal experiment N = 5290 Species

  2. Upupa epops

  3. Great Tit Parus major David Lack

  4. Parus major

  5. European Starling, Sturnus vulgaris

  6. Chimney Swift, Apus apus

  7. Seabirds (N. Philip Ashmole) Boobies,Gannets, Gulls, Petrels, Skuas, Terns, Albatrosses Delayed sexual maturity, Small clutch size, Parental care

  8. Albatross Egg Addition Experiment An extra chick added to each of 18 nests a few days after hatching. These nests with two chicks were compared to 18 other natural “control” nests with only one chick. Three months later, only 5 of the 36 experimental chicks survived from the nests with 2 chicks, whereas 12 of the 18 chicks from single chick nests were still alive. Parents could not find food enough to feed two chicks and most starved to death. Diomedea immutabilis

  9. Latitudinal Gradients in Avian Clutch Size

  10. Latitudinal Gradients in Avian Clutch Size Daylength Hypothesis Prey Diversity Hypothesis Spring Bloom or Competition Hypothesis

  11. Latitudinal Gradients in Avian Clutch Size Nest Predation Hypothesis Alexander Skutch ––––––>

  12. Latitudinal Gradients in Avian Clutch Size Hazards of Migration Hypothesis Falco eleonora

  13. Evolution of Death RatesSenescence, old age, genetic dustbin Medawar’s Test Tube Modelp(surviving one month) = 0.9p(surviving two months) = 0.92p(surviving x months) = 0.9xrecession of time of expression of the overt effects of a detrimental alleleprecession of time of expression of the effects of a beneficial allele Peter Medawar

  14. Age Distribution of Medawar’s test tubes

  15. Percentages of people with lactose intolerance

  16. Joint Evolution of Rates of Reproduction and Mortality Sceloporus Donald Tinkle

  17. J - shaped exponential population growth http://www.zo.utexas.edu/courses/THOC/exponential.growth.html

  18. Instantaneous rate of change of N at time tis total births (bN) minus total deaths (dN)dN/dt = bN – dN = (b – d )N = rNNt = N0 ert (integrated version of dN/dt = rN)log Nt = log N0 + log ert = log N0 + rtlog R0 = log 1 + rt (make t = T)r = log l or l = er (l is the finite rate of increase)

  19. Once, we were surrounded by wilderness and wild animals, But now, we surround them.

  20. S - shaped sigmoidal population growth

  21. Verhulst-Pearl Logistic Equation dN/dt = rN – rN (N/K) = rN – {(rN2)/K}dN/dt = rN {1– (N/K)} = rN [K/K – N/K]dN/dt = rN {1– (N/K)} = rN [(K – N)/K] dN/dt = 0when[(K – N)/K] = 0[(K – N)/K] = 0when N = K dN/dt = rN (1 – N/K) = rN – (r/K)N2

More Related