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C1: The Equation of a Straight Line, lesson 2. Learning Objective : to be able to find the equation of a straight line in the form y – y 1 = m(x - x 1 ). Starter:. Write the equation of the line y = ½ x + 5 in the form ax + by + c = 0.
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C1: The Equation of a Straight Line, lesson 2 Learning Objective : to be able to find the equation of a straight line in the form y – y1 = m(x - x1)
Starter: • Write the equation of the line y = ½ x + 5 in the form ax + by + c = 0. • A line, parallel to the line 6x + 3y – 2 = 0, passes through the point (0,3). Work out the equation of the line.
Finding the equation of a line y P(x, y) A(x1, y1) So 0 x Suppose a line passes through A(x1, y1) with gradient m. Let P(x, y) be any other point on the line. y – y1 x – x1 This can be rearranged to give y – y1 = m(x – x1). In general: The equation of a line through A(x1, y1) with gradient m is y – y1 = m(x – x1)
Finding the equation of a line y B(5, 4) 0 x A(3, –2) • Finding the equation of a line given two points on the line A line passes through the points A(3, –2) and B(5, 4). What is the equation of the line? The gradient of AB, m = Therefore the gradient of AB is 3 .
Finding the equation of a line Substituting m = 3 and a co-ordinate pair, A(3, –2), into the equationy – y1 = m(x – x1) gives y + 2 = 3(x – 3) y + 2 = 3x – 9 y = 3x – 11 So, the equation of the line passing through the points A(3, –2) and B(5, 4) is y = 3x – 11.
Example Find the equation of the line with gradient ½ that passes through (-1, -4). Using y – y1 = m (x – x1) y- (-4) = ½ ( x – (-1)) y + 4 = ½ x + ½ y = ½ x - 3 ½ 2y – x + 7 = 0
Task 1 : Work out the gradient of the line joining these pairs of points • (4, 2) (6, 3) • (-4, 5) (1, 2) • (-3, 4) (7, -6) • (1/4, ½) (1/2, 2/3) • (3b, -2b) (7b, 2b) • The line joining (3, -5) to (6, a) has a gradient of 4. Calculate the value of a.
Task 2 : Find the equation of the line when: • m = 2, (x1, y1) = ( 2, 5) • m = -1, (x1, y1) = ( 3, -6) • m = ½, (x1, y1) = ( -4, 10) • (x1, y1) = ( 2, 4), (x2, y2) = ( 3, 8) • (x1, y1) = ( 0, 2), (x2, y2) = ( 3, 5) • (x1, y1) = ( 5, -3), (x2, y2) = ( 7, 5) • (x1, y1) = ( -1, -5), (x2, y2) = ( -3, 3) • (x1, y1) = ( 1/3, 2/5), (x2, y2) = ( 2/3, 4/5)
Task 3 • The line y = 4x -8 meets the x-axis at the point A. Find the equation of the line with gradient 3 that passes through the point A. • The line y = ½ x + 6 meets the x-axis at point B. Find the equation of the line with gradient 2/3 that passes through the point B. Write your answer in the form ax + by + c = 0 where a, b and c are integers. • The lines y = x - 5 and y = 3x – 13 intersect at the point C. The point D has co-ordinates (-4, 2). Find the equation of the line that passes through the points C and D.